It is the condition used after the if condition. say you use the if condition and you need to add another outcome, instead of using the if condition again, you’d use elif and end it with the else command.
example:
if num == 10:
print (“correct”)
elif num > 10:
print (“too high”)
else:
print (”too low”)
hope this helps :]
Answer:
The main advantage of the special-purpose systems is the possibility to utilize a much higher fraction of available silicon to actually do calculations. ... All the rest of the calculation, such as the time integration of the orbits of particles, I/O, and diagnostics are handled by a general-purpose host computer..
Explanation:
The correct answer is Choice D.
In order to adjust an image on a slide you can resize it by clicking on the boxes at the corner and then moving it in or out in order to change its size.
Answer:
#include <iostream>
#include<iomanip>
using namespace std;
double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)
{
double dollarCost = 0;
dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;
return dollarCost;
}
int main()
{
double miles = 0;
double dollars = 0;
cout << "Enter miles per Gallon : ";
cin >> miles;
cout << "Enter dollars per Gallon: ";
cin >> dollars;
cout << fixed << setprecision(2);
cout << endl;
cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;
cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;
cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;
return 0;
}
Explanation:
- Create a method definition of DrivingCost that accepts three input double data type parameters drivenMiles, milesPerGallon, and dollarsPerGallon and returns the dollar cost to drive those miles
.
- Calculate total dollar cost and store in the variable, dollarCost
.
- Prompt and read the miles and dollars per gallon as input from the user
.
- Call the DrivingCost function three times for the output to the gas cost for 10 miles, 50 miles, and 400 miles.
