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Nuetrik [128]
3 years ago
14

Write a static method named contains that accepts two arrays of integers a1 and a2 as

Computers and Technology
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

Sew explaination foe code

Explanation:

import java.lang.*;

import java.util.*;

import java.io.*;

class Main

{

public static Boolean checkSubset(int[] list1, int[] list2)

{

int l = list2.length;

for(int i = 0; i<list1.length-l; i++)

{

Boolean flag = true;

for(int j = 0; j<list2.length; j++)

{

if(list1[i+j] != list2[j])

{

flag = false;

break;

}

}

if(flag) return true;

}

return false;

}

public static void main(String args[])

{

int[] l1 = {1,6,2,1,4,1,2,1,8};

int[] l2 = {1,2,2};

System.out.println(checkSubset(l1,l2));

}

}

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What is the function of a bread crumb trial in a website
joja [24]

Answer:

A “breadcrumb” (or “breadcrumb trail”) is a type of secondary navigation scheme that reveals the user's location in a website or Web application. The term comes from the Hansel and Gretel fairy tale in which the two title children drop breadcrumbs to form a trail back to their home.

Explanation:

A breadcrumb or breadcrumb trail is a graphical control element frequently used as a navigational aid in user interfaces and on web pages. It allows users to keep track and maintain awareness of their locations within programs, documents, or websites. Breadcrumbs make it easier for users to navigate a website – and they encourage users to browse other sections of the site. ... You head to their site and end up on The Nestle company history page. Using their breadcrumbs, you can easily navigate back to About Us, History, or even their home page.

6 0
3 years ago
Given f(x) = -2x2 + 5x - 1 and g(x) = 3x + 4 determine a simplified
lukranit [14]

Answer:

-6x^4 + 7x^3 + 17x^2 -4x

Explanation:

( f x g )( x )

Substitute

[( -2x^2 + 5x -1 )( 3x + 4 )]( x )

Use the Distributive Property

[-2x^2( 3x) + 5x( 3x) - 1( 3x) -2x^2( 4) + 5x (4) -1 (4)] (x)

Simplify

( -6x^3 + 7x^2 + 17x -4)(x)

Distributive Property

-6x^4 + 7x^3 + 17x^2 -4x

7 0
4 years ago
Flujograma de nómina ​
balu736 [363]
Explanation there is the rest in comments

7 0
2 years ago
This project must target a Unix platform and execute properly on our CS1 server.
sweet-ann [11.9K]

Answer:

hope this helps ,if it did pls do consider giving brainliest

Explanation:

// Java program for implementation of FCFS scheduling

import java.text.ParseException;

class GFG {

// Function to find the waiting time for all

// processes

static void findWaitingTime(int processes[], int n,

int bt[], int wt[]) {

// waiting time for first process is 0

wt[0] = 0;

// calculating waiting time

for (int i = 1; i < n; i++) {

wt[i] = bt[i - 1] + wt[i - 1];

}

}

// Function to calculate turn around time

static void findTurnAroundTime(int processes[], int n,

int bt[], int wt[], int tat[]) {

// calculating turnaround time by adding

// bt[i] + wt[i]

for (int i = 0; i < n; i++) {

tat[i] = bt[i] + wt[i];

}

}

//Function to calculate average time

static void findavgTime(int processes[], int n, int bt[]) {

int wt[] = new int[n], tat[] = new int[n];

int total_wt = 0, total_tat = 0;

//Function to find waiting time of all processes

findWaitingTime(processes, n, bt, wt);

//Function to find turn around time for all processes

findTurnAroundTime(processes, n, bt, wt, tat);

//Display processes along with all details

System.out.printf("Processes Burst time Waiting"

+" time Turn around time\n");

// Calculate total waiting time and total turn

// around time

for (int i = 0; i < n; i++) {

total_wt = total_wt + wt[i];

total_tat = total_tat + tat[i];

System.out.printf(" %d ", (i + 1));

System.out.printf(" %d ", bt[i]);

System.out.printf(" %d", wt[i]);

System.out.printf(" %d\n", tat[i]);

}

float s = (float)total_wt /(float) n;

int t = total_tat / n;

System.out.printf("Average waiting time = %f", s);

System.out.printf("\n");

System.out.printf("Average turn around time = %d ", t);

}

// Driver code

public static void main(String[] args) throws ParseException {

//process id's

int processes[] = {1, 2, 3};

int n = processes.length;

//Burst time of all processes

int burst_time[] = {10, 5, 8};

findavgTime(processes, n, burst_time);

}

}

// Java program to implement Shortest Job first with Arrival Time

import java.util.*;

class GFG {

static int[][] mat = new int[10][6];

static void arrangeArrival(int num, int[][] mat) {

for (int i = 0; i < num; i++) {

for (int j = 0; j < num - i - 1; j++) {

if (mat[j][1] > mat[j + 1][1]) {

for (int k = 0; k < 5; k++) {

int temp = mat[j][k];

mat[j][k] = mat[j + 1][k];

mat[j + 1][k] = temp;

}

}

}

}

}

static void completionTime(int num, int[][] mat) {

int temp, val = -1;

mat[0][3] = mat[0][1] + mat[0][2];

mat[0][5] = mat[0][3] - mat[0][1];

mat[0][4] = mat[0][5] - mat[0][2];

for (int i = 1; i < num; i++) {

temp = mat[i - 1][3];

int low = mat[i][2];

for (int j = i; j < num; j++) {

if (temp >= mat[j][1] && low >= mat[j][2]) {

low = mat[j][2];

val = j;

}

}

mat[val][3] = temp + mat[val][2];

mat[val][5] = mat[val][3] - mat[val][1];

mat[val][4] = mat[val][5] - mat[val][2];

for (int k = 0; k < 6; k++) {

int tem = mat[val][k];

mat[val][k] = mat[i][k];

mat[i][k] = tem;

}

}

}

// Driver Code

public static void main(String[] args) {

int num;

Scanner sc = new Scanner(System.in);

System.out.println("Enter number of Process: ");

num = sc.nextInt();

System.out.println("...Enter the process ID...");

for (int i = 0; i < num; i++) {

System.out.println("...Process " + (i + 1) + "...");

System.out.println("Enter Process Id: ");

mat[i][0] = sc.nextInt();

System.out.println("Enter Arrival Time: ");

mat[i][1] = sc.nextInt();

System.out.println("Enter Burst Time: ");

mat[i][2] = sc.nextInt();

}

System.out.println("Before Arrange...");

System.out.println("Process ID\tArrival Time\tBurst Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2]);

}

arrangeArrival(num, mat);

completionTime(num, mat);

System.out.println("Final Result...");

System.out.println("Process ID\tArrival Time\tBurst" +

" Time\tWaiting Time\tTurnaround Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2], mat[i][4], mat[i][5]);

}

sc.close();

}

}

7 0
3 years ago
Match the words (1-10) with the definitions (A-J)
sergij07 [2.7K]

Answer:

1 - I

2 - A

3 - B

4 - E

5 - J

6 - C

7 - H

8 - D

9 - F

10 - G

3 0
3 years ago
Read 2 more answers
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