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uranmaximum [27]
3 years ago
9

What font family is Times New Roman an what font family is Arial?

Computers and Technology
2 answers:
padilas [110]3 years ago
5 0

Answer:

  1. R family Font on Windows Font on Unix
  2. sans Arial Arial
  3. serif Times New Roman Times
  4. mono Courier Courier
  5. symbol Standard Symbols L Symbol

Alexxandr [17]3 years ago
4 0

Answer:

Some Font Examples

Generic Font Family                 Examples of Font Names

Serif                    Times New Roman Georgia Garamond

Sans-serif                          Arial Verdana Helvetica

Monospace                     Courier New Lucida Console Monaco

Cursive                        Brush Script MT Lucida Handwriting

Explanation:

hope it help

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Write a program that prompts the user to enter the number of integer numbers you need to enter, then ask user to enter these int
nadya68 [22]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner ob = new Scanner(System.in);

 System.out.println("How many numbers? ");

 int n = ob.nextInt();

       int[] arr = new int[n];  

 for (int i=0; i<n; i++) {

     System.out.print("Enter the number: ");

     arr[i] = ob.nextInt();

 }

    System.out.println(indexOfLargestElement(arr));

}

public static int indexOfLargestElement(int[] arr) {

    int max = arr[0];

    int maxIndex = 0;

    for (int i=0; i<arr.length; i++) {

        if (arr[i] >= max) {

            max = arr[i];

            maxIndex = i;

        }

    }

    return maxIndex;

}

}

Explanation:

Create a method called indexOfLargestElement that takes one parameter, an array

Initialize the max and maxIndex

Create a for loop iterates throgh the array

Check each element and find the maximum and its index

Return the index

Inside the main:

Ask the user to enter how many numbers they want to put in array

Get the numbers using a for loop and put them inside the array

Call the indexOfLargestElement method to find the index of the largest element in the array

8 0
3 years ago
Please debug the below code in Java please.
lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

           int invoiceNumber;

           string customer;

           double balanceDue;

           double tax;

//class methods

public:

           void setCustomer(string cus);

           void displayInvoice();

           void setBalanceDue(double balance);

           void setInvoiceNUMBER(int number);

           void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

       invoiceNumber = 0;

else

   invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0
3 years ago
What type of computer is IBM 1401 ?<br><br>​
rjkz [21]

Answer:

The IBM 1401 is a variable-word length decimal computer that was announced by IBM on October 5, 1959.

7 0
2 years ago
The capacity of a communication channel is measured in _______.
PSYCHO15rus [73]
<span>The capacity of a communication channel is measured in gb and gps.</span>
4 0
3 years ago
Read 2 more answers
What is the first and last value of i to be displayed by the following code snippet? int n = 20; for (int i = 0; i &lt;= n; i++)
frutty [35]

Answer:

The first value of i is 0 and last value of i is 20.

Explanation:

The following are the description of a given loop.

  • In this problem, there are two loops one is the internal loop and the other is the external loop
  • In the outer loop, the value of " i" is initialized with "0" So the first value is printed 0 in the console.
  • For one value of "i" all the inner loop is executed.
  • The loop is executed is less equal to 20 that's why the last value of "i" is printed 20 in the console window.

6 0
3 years ago
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