That is where the line crosses the x axis or where y=0
0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48
what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0
8x+1=0
8x=-1
x=-1/8
-2x+3=0
3=2x
3/2=x
x intercepts ate x=-1/8 and x=3/2
43 - 18*2 = 43 -36 = 7
7 were 3 point shots
11 were 2 point shots
Answer:
The expression that represents the given sequence is 5+6(n-1). Option C (not labeled).
Explanation:
<u>Arithmetic Sequences</u>
In an arithmetic sequence, each term can be obtained by adding or subtracting a fixed number to the previous term. That fixed number is called the common difference.
We are given the following sequence:
5, 11, 17, 23, 29, ...
Each term is located in a position starting from n=1. Let's test each option:
A For n=1 we should have the first term (5). Substituting n=1 into the general equation: 5+6(n+1) = 5+6(1+1) = 5+12 = 17. Since the resulting term is not 5, this option is incorrect.
B For n=1, 6+5(n+1)= 6+5(2)=16. This option is incorrect.
C (not labeled) For n=1, 5+6(n-1)=5+6(1-1)=5+0=5. The first term is correct. Let's test for the second term (n=2):
5+6(2-1)=5+6=11. Correct. For n=3
5+6(3-1)=5+12=17. Correct.
We can see the terms are increasing by 6, and the given sequence is also increasing by 6. Thus, This option is correct.
D For n=1, 6+5 (n-1)=6+0=6. This option is incorrect.
Answer:
14 home runs
Step-by-step explanation:
This is basically a subtraction problem.
So the maximum number is 60 home runs in 1927.
The minimum number is 46 home runs in 1929.
So you subtract these 2 values.
60 - 46
= 14
So the maximum number exceed the minimum number with 14 home runs as the difference.
