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andriy [413]
2 years ago
13

What is my mystery number???

Mathematics
2 answers:
sammy [17]2 years ago
7 0

Answer: 25

Step-by-step explanation:

To figure out the mystery number, the biggest clue we have is the fact that the number is a double digit and the 2 integers add up to 7. We can list out the possible ways to get a sum of 7. Then we can see which is the mystery number.

0+7

1+6

2+5

3+4

With these pairs, we can automatically eliminate 0+7 because 70 is greater than 30. We can also eliminate 3+4 because 34 is even, not odd. When you flip it to 4+3, it is odd, but it is greater than 30. We can also eliminate 1+6 because 16 is even and 61 is greater than 30. Our answer is 25. 2+5=7 and 25 is odd that is less than 30.

mars1129 [50]2 years ago
5 0

Answer:

25

Step-by-step explanation:

25 has 2 digits

25 is less than 30

25 is odd

2+5 = 7

It is 25.

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B, 2 5/8.

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Fill in the blanks to express the quantities given in ratio language. Ratios must be
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Step-by-step explanation:

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ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R
shutvik [7]

Answer:

A'= (2,-1) and R'=(4,-2) under this translation.

Step-by-step explanation:

A translation in R^{2} is a mapping T from R^{2} to R^{2}  defined by T(x,y) = (x + v_1,y+v_2), where v=(v_1,v_2) is a fixed vector in R^{2}.

From the problem we know that T(2,4)=(3,2), so we need to find the values v_1 and v_2 such that  T(2,4) = (2 + v_1,4+v_2)=(3,2), so 3=2 + v_1 and 4+v_2=2, thus v_1=1 and v_2=2.

Then T(x,y) = (x + 1,y-2) and  

T(1,1)=(1+1,1-2)=(2,-1)=A'

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Therefore A'= (2,-1) and R'=(4,-2). The triangles CAR and C'Q'R' are shown in the figure below.

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3 years ago
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3 years ago
Read 2 more answers
HELP!!<br>Find the third term of (x^2+3y)^3
lana66690 [7]

Answer:

T_{3}=27{x}^{2}y^2

Step-by-step explanation:

The given binomial expression is:

( {x}^{2} + 3y)^{3}

When we compare to:

{(a +b)}^{n}

We have

a =  {x}^{2}

b = 3y \\ n = 3

The nth term is given by;

T_{r+1}=^nC_ra^{n-r}b^r

To find the 3rd term, we put:

r + 1 = 3 \\ r = 2

We substitute into the formula to get:

T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2

We simply:

T_{3}=3( {x}^{2} )^{1} \times 9y^2

T_{3}=27{x}^{2}y^2

3 0
3 years ago
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