Answer:
c.5
Step-by-step explanation:
5(3 + 2 + 8)
The number outside of the parenthesis is distributed to the numbers inside of the parenthesis
For this case we have the following equation:
![y = -2x ^ 2 + 4x + 12 ](https://tex.z-dn.net/?f=y%20%3D%20-2x%20%5E%202%20%2B%204x%20%2B%2012%0A)
Deriving we have:
![y = -2x ^ 2 + 4x + 12 y '= -4x + 4](https://tex.z-dn.net/?f=y%20%3D%20-2x%20%5E%202%20%2B%204x%20%2B%2012%0A%0Ay%20%27%3D%20-4x%20%2B%204)
We match zero:
![-4x + 4 = 0 ](https://tex.z-dn.net/?f=%20%20-4x%20%2B%204%20%3D%200%0A)
We clear the value of x:
![4x = 4 x = 4/4 x = 1](https://tex.z-dn.net/?f=4x%20%3D%204%0A%0Ax%20%3D%204%2F4%0A%0Ax%20%3D%201)
Then, we substitute the value of x in the equation of the parabola:
![y = -2 (1) ^ 2 + 4 (1) + 12 y = -2 + 4 + 12 y = 14](https://tex.z-dn.net/?f=y%20%3D%20-2%20%281%29%20%5E%202%20%2B%204%20%281%29%20%2B%2012%0A%0Ay%20%3D%20-2%20%2B%204%20%2B%2012%0A%0Ay%20%3D%2014)
Thus, the vertex of the parabola is the ordered pair:
Answer:
The vertice is:
Answer:
Given that The data to represent average test scores for a class of 16 students includes an outlier value of 78.
We can find sum of all 16 test scores = 84(16) = 1344
Outlier found = 78
If outlier is removed new sum = 1344-78 = 1266
Number of entries without outlier = 15
New average = 1266/12 =84.4
We find that average of new data increases.
Also whenever we remove outlier std deviation also would be reduced.
Step-by-step explanation:
Answer: 1760
Step-by-step explanation:
Cost of 1 flyer = $0.25 or 25 cents
Budget is = $555
Let us assume that supplies cost is a one time cost
Cost of supplies for one time = $115
So budget remains =
So in $0.25 we get = 1 flyer
In $440 we get = = 1760
Hence, we can buy 1760 flyers.
hope this helped
Answer:
23 units
Step-by-step explanation:
Use the distance formula: d = ![\sqrt{(x2 - x1)^2 + (y2 - y1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x2%20-%20x1%29%5E2%20%2B%20%28y2%20-%20y1%29%5E2%7D)
Plug in the 2 points:
d = ![\sqrt{(-12 - 11)^2 + (-4 + 4)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-12%20-%2011%29%5E2%20%2B%20%28-4%20%2B%204%29%5E2%7D)
d = ![\sqrt{529}](https://tex.z-dn.net/?f=%5Csqrt%7B529%7D)
d = 23
So, the distance is 23 units