Answer:
- 30 adult tickets,
- 50 kids tickets
Step-by-step explanation:
<u>Given</u>
- Cost of adult ticket = $8.50
- Cost of kids ticket = $7.00
- Number of tickets = 80
- Total cost = $605
Let the adult ticket be a and kids be k
<u>We got equations</u>
- a + k = 80
- 8.5a + 7k = 605
<u>From the first equation we get</u>
<u>Substituting k in the second equation</u>
- 8.5a + 7(80 - a) = 605
- 8.5a - 7a + 560= 605
- 1.5a = 45
- a = 45/1.5
- a = 30
<u>Then finding k</u>
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
Answer: D. a+2s=$22
a+3s=$28
Step-by-step explanation:
Let's take a look at our variables. They are a and s, the a standing for the cost of an adult ticket and the s standing for the cost of the student ticket. In both situations, only one adutl ticket was purchased, so we start off out equations with only an a. As for the student tickets, Alex buys 2 and Jen buys 3.
a+2s
a+3s
The whole point of writing this equation is to find the cost of the tickets, so we would both equal it to the amount they spent.
a+2s=$22
a+3s=$28
