Answer:
43 dollars
Step-by-step explanation:
to take the average we have to add up all the numbers and divide by 5 which is
215/5=43
if my answer helps please mark as brainliest.
A represents the speed of the aircraft.
b represents the speed of the bus.
a=2b-5
114/b=218/a
Substitution method
114/b=218/(2b-5)
(2b-5)*(114/b)= 218
(228b-570)/b = 218
228b-570= 218b
228b-218b=570
10b= 570
b=57
Plug the value of b into one of the original equations.
a=2(57)-5
a=114-5
a=109
Final answer:
Average speed of plane= 109
Average speed of bus= 57
20*15=300
It's "too short", but there's not much else to say here.
<h3>17 heavy equipment operators and 14 general labourers were employed</h3>
<em><u>Solution:</u></em>
Let x = number of heavy equipment operators employed
Then,
31 - x = number of laborers employed
From given,
Pay of heavy equipment operators = $ 138 per day
Pay of general labours = $ 93 per day
Payroll was $3648
Therefore,
number of heavy equipment operators x Pay of heavy equipment operators + number of laborers employed x Pay of general labours = 3648
138x + 93(31 - x) = 3648
138x + 2883 - 93x = 3648
45x = 3648 - 2883
45x = 765
x = 17
Thus,
31 - x = 31 - 17 = 14
Therefore, 17 heavy equipment operators and 14 general labourers were employed
