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fiasKO [112]
2 years ago
6

Una caja tiene 60 bombones eba se comio 1/5 bombones y ana 1/2 bombones cuantos bombones se comio eba y ana

Mathematics
1 answer:
DedPeter [7]2 years ago
7 0

Responder:

42 bombones

Explicación paso a paso:

Dado que :

Número de bombones = 60

Cantidad consumida por Eba = 1/5 * 60 = 12

Cantidad comida por Ana = 1/2 * 60 = 30

Cantidad de chocolate que comieron Eba y Ana:

(12 + 30) = 42

De ahí que Ana y Eba se comieran 42 bombones

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3 years ago
2. The pool maintenance man forgot to bring his logarithmic charts, and he needs to raise
rusak2 [61]

Answer:

hey have made this a little more confusing than it has to be. Usually we use H+ in chemistry instead of t, but you can also use X, Y if it's easier where Y = -log(X) where X= hydronium and Y = pH.

Which also means Y=p(t) and X = t.

To graph this, I would suggest using values for X like 0.1, 0.2, 0.5, 0.7, 1.0, 1.5, or similar numbers. Then use your calculator to calculate Y values for each of these X values and plot them. You can also use a spreadsheet. If you have Excel I can help you to use it. Either way you can then use your graph to answer the questions in part 1 where Y = 0 and Y=1 and just read off the X values.

Part 2 is worded badly. It's ambiguous to say "raised by 0.5" since if you raise hydronium (= X) by 0.5, the change in pH (=Y) will vary depending on where you start. They meant "raise to 0.5", though they do say this at the end of the question. Anyway, you can easily read it off your graph using 0.5 as the X value.

Now to set up the exponential function this is much easier than it sounds. Just remember that a logarithm is the inverse of an exponent so they cancel each other out:  As an example log(10X) = X.

So applying here, just take this equation  Y = -log(X) and raise 10 to both sides of the equation:

10Y = 10-log(X)    which gives you 10Y = 1/X or more usefully X = 10-Y where again X= hydronium and Y = pH

Part 3, these questions actually have no relationship to anything in chemical reality, but are just exercises to see if you can manipulate the graph and function. But they do illustrate at least one interesting point. Note that in the equation

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Y = -log(X)

You know X can also never be zero since you can't have log(0).

Now when they ask for a "Y intercept" they are asking for when X=0 which as stated is never in the above case. However when you transform the equation the ways they want you to, then maybe sometimes you can:

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But p(t+1) really means Y = -log(X+1). Here of course X can be zero since that just gives you log(1). So you have a Y-intercept.

I'll leave it for you to figure out the third one, the question being if you set X=0, will you get log(0)? If so, that's forbidden. If not, you will have a Y intercept.

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Answer:

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Answer:

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