An exterior angle is equal to the sum of the 2 non adjacent angles. In this case
100 = x + 70 Subtract 70
x = 100 - 70
x = 30
48 miles/4hrs = 12 mph
Increased Speed 12 mph + 8mph = 20 mph
Distance left 108 miles - 48 miles = 60 miles
Time left 60 miles/20 mph = 3 hours
The mean is 35/5=7
The variance is the average of the sum of squared differences of each element from the mean:
v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5
v=(0+4+16+36+16)/5
v=14.4
Q3-Q1=IQR is the formula.
For this case we have the following equation:
h = -16t ^ 2 + 32t + 6
Deriving we have:
h '= -32t + 32
We equal zero and clear t:
-32t + 32 = 0
32t = 32
t = 32/32
t = 1 s
Then, the maximum height is given by:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
It takes the ball to reach its maximum height about:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
