First you plug in the missing values
y=3 x=4 z=2
3÷2×4-2
than you solve
the answer is 4
Answer:
MMM
Step-by-step explanation:
Given
See attachment for elements of the sample space (in a probability tree)
Required
Which of MMM, FFM, MFF, FMF represents more than one male?
From the question, we understand that:
So, for an event to represent more than 1 male, there must be an occurrence of at least 2 M (i.e 2 M or 3 M)
From the given options, only MMM has more than 1 M.
Hence, MMM represents more than one Male
40
There isnt a way the LCD can go lower, because 5 only counts by 5's and 5 and 8 meet at 40.
Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.
The correct answer for the exercise shown above is:
zero (0)
The explanation is shown below:
1. You have the following expression given in the problem above:
7/6a
2. By definition, <span>the nonpermissible replacement for a is the value that make the denominator equal to zero.
3. Keeping this on mind, you have:
7/6a=7/6(0)=7/0
Therefore, as you can see, the answer is: zero (a=0).
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