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krok68 [10]
3 years ago
13

The hands of a clock suggest an angle whose measure is continually changing. How many degrees does a minute hand move through du

ring a 26​-minute time​ interval?
Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

The minute hand covers 156^o  in 26 minutes

Step-by-step explanation:

Notice that the minute hand of a clock covers 360 degrees angle (full rotation) in 60 minutes.

Then if we want to find how many degrees (our unknown x) it covers in 26 minutes, we can write the following proportion to solve for the unknown:

\frac{360^o}{60} =\frac{x}{26}\\x=\frac{(26)\,360^o}{60} \\x=156^o

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Write an equation for a line parallel to y=2x-2 and passing through the point (1,1) Y=???? PLEASE HELP ANYONE
Rufina [12.5K]
The general equation for slope-intercept form is y = mx + b, where m = the slope of the equation, b = the y intercept, and x and y are your variables (and the coordinate points on the graph). 

Remember that for parallel lines, the slope, m, is the same for both equations. The equation you're given, y = 2x - 2, is already in slope-intercept form and the 2 in front of x is m, your slope. That means for whatever equation we come up with, m has to be 2. 

So far we know the equation for our parallel line is y = 2x + b. How do we figure out b? Plug in the (x, y) coordinate you're given, (1, 1) and solve for b:
y = 2x + b\\
1 = 2(1) + b\\
1 = 2 + b\\
b = -1

Now we know b = -1. Put that into our y = 2x + b equation to get the final equation of your parallel line: 
Your final answer is y = 2x - 1.

5 0
3 years ago
Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro
tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation  

n=2700 represent the random sample taken    

X represent the people in England who are deficient in Vitamin D

\hat p=0.2 estimated proportion of England people who are deficient in Vitamin D

\alpha=0.02 represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)    

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

And replacing into the confidence interval formula we got:

0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182

0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0
3 years ago
Round to the Nearest Ten
lora16 [44]

Answer:

Step-by-step explanation:

62 to the nearest ten is 60.

6 0
3 years ago
A teacher asks students to list the math lessons they learned on nine random school days in the past month. She evaluates the st
zysi [14]

Answer:

Simple random sampling

Step-by-step explanation:

Hope this work :)

5 0
2 years ago
How to solve 2/10b=99
soldier1979 [14.2K]
Multiply both sides by 10.
2b=990
divide both sides by 2
b= 495
6 0
3 years ago
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