Answer:
0.81859
Step-by-step explanation:
We solve using z score method
The formula for calculating a z-score is is z = (x-μ)/σ,
where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Mean 0.8 pound
Standard deviation 0.25 pound
For x = 0.55 pound
z = 0.55 - 0.8/0.25
= -1
Probability -value from Z-Table:
P(x = 0.55) = 0.15866
For x = 1.3 pounds
Z = 1.3 = 0.8/0.25
= 2
Probability value from Z-Table:
P(x = 1.3) = 0.97725
The probability that a randomly selected zucchini will weigh between 0.55 pound and 1.3 pounds is
P(x = 1.3) - P(x = 0.8)
0.97725 - 0.15866
0.81859.
What do you mean? Please message me the question and I will gladly help
A) it is left skewed
B) the median is 5
C) the mean is 5.15
D) the mean would be more affected (a change of 1.05 versus a change of 0.5).
The majority of the data is to the right of the graph; this means it is left skewed.
To find the median, write all of the data values out:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7
The middle value is 5.
We find the sum of this set of values and divide by 13, the number of data points, to find the mean:
2+3+4+4+5+5+5+6+6+6+7+7+7 = 67/13 = 5.15
If we added an additional data value at 20, the new median would be 5.5. The new mean would be (67+20)/14 = 6.2. The mean changes more than the median.
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%
