Area 1 = 175.84
area 2 = 156.30
area 1: A=(pi)r^2 x 140/360
in this case we would use the degree of the entire circle and the degree of the sector since it is not given.
area 2: A=(pi)r^2 x 280/360
in this case we would use the degree of the entire circle and the degree of the sector since it is not given.
Answer:
145
Step-by-step explanation:
6+(5+1)
(5+1)=6
6(6)
6x6= 36
Answer:
1529.4 m^3
Step-by-step explanation:
We will use the formula V = 1/3*h*B for the volume of the pyramid, where V is volume, h is height, and B is are of the base.
First, since we know h and are looking for V, we need B. To find this, since it has a square base, we multiply b, the base length, by itself. 15.3m * 15.3m = 234.09m^2.
Next, we plug into the formula.
V = 1/3*19.6m*234.09m^2
And simplify:
V= 1/3 * 4,588.164m^3
V= 15.29.3879....
Last, round to the tenth
1529.4 m^3
Answer:
10
Step by step explanation:
In general, if we have an equation that has just one variable, such as x, then "solving the equation" means finding the set of all values that can be substituted for the one variable to produce a valid equation.
Isolate "x" on one side of the algebraic equation by adding the negative number that appears on the same side of the equation as the "x." For example, in the equation "x - 5 = 12", rewrite the equation as "x = 12 + 5" and solve for "x."
x + (-6) + (-8) = -4
x + (-6 + -8) = -4
x + (-14) = -4
x + (-14 + 14) = -4 + 14
x = 10
