People are kinda rude sometimes
Sqrt(x) - 5+7 =11
combine like terms
-5 +7 = 2
sqrt(x) + 2 = 11
subtract 2 from each side
sqrt(x) = 9
square both sides
x = 9^2
x = 81
an extraneous solution would be an invalid solution
in this case it is not an extraneous solution
The answer is B. The way you find it is through substitution. First use the coordinate (0, 1/2) in y = ax^2 + c to solve for c: 1/2=a(0)^2 + c--> 1/2=c. Now use that c value in the same y = ax^2 + c equation with the other coordinate to solve for a: 73/2 = a(-3)^2 + 1/2. Subtract 1/2 from both sides to get 72/2=9a. 72/2 is 36. So 36 = 9a...a = 4. Now fill in your a and your c to get y = 4x^2 + 1/2
Im pretty sure the last one is right.
The advantage is that you can visibly see the difference in the data. Disadvantage of line plots would be that not as appealing.