Question

A golfer takes an uphill shot towards the hole, and they make the shot. The path of the ball can be modeled by the equation y=-5^2– 40x– 10, where x is the horizontal distance and y is the vertical distance traveled by the ball in meters. How much higher is the hole than the spot from where the shot was taken? The hole is meters higher What was the maximum height above the hole that the ball reached while it was in the air? meters The maximum height that the ball reached above the hole was What was the horizontal distance that the ball traveled from the point that the shot was taken to the hole? Round your ai the nearest tenth of a meter. meters. The horizontal distance covered by the ball was​

Answer 1

Answer:

Solve for n

n=log5  (− 2 /y  −20x−5),y<−40x−10

Step-by-step explanation: