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3 years ago

13

A worker wishes to calculate his new salary after a 20% pay raise if X represents his current pay what expressions can be used t

o calculate his new rate of pay.

1 answer:

FrozenT [24]3 years ago

4 0

You can use the expression: New Salary = (120/100) * X

You could also simplify 120/100 to 6/5

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Which system of equations is represented by the matrix below?

katrin [286]

Answer:

B

Step-by-step explanation:

4 0

3 years ago

WILL MARK AS BRAINLIEST IF YOU ANSWER THESE CORRECTLY*** Can someone please help me with these math questions? I would really ap

igor_vitrenko [27]

ANSWER:

Question a):

$\dfrac{5}{3}*x= \dfrac{5}{6}\\ \\ \\ \dfrac{5}{3}x= \dfrac{5}{6}\\ \\6(5x)=3(5)\\ \\30x=15\\ \\x= \dfrac{15}{30}\\ \\ \\x= \dfrac{\not{15}}{\not{30}}\\ \\ \\x= \dfrac{1}{2}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question b):

$\dfrac{5}{3}\div{x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3}\div{ \dfrac{x}{1} }= \dfrac{10}{9}\\ \\ \\ \dfrac{5*1}{3*x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3x}= \dfrac{10}{9}\\ \\9(5)=10(3x)\\ \\45=30x\\ \\ \dfrac{45}{30}=x\\ \\ \\ \dfrac{\not{45}}{\not{30}}=x\\ \\ \\ \dfrac{3}{2}=x\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question c):

$12\%*x= \dfrac{3}{4}\\ \\ \\ \dfrac{12}{100}*x= \dfrac{3}{4}\\ \\ \\ \dfrac{\not{12}}{\not{100}}x= \dfrac{3}{4}\\ \\ \\ \dfrac{3}{25}x= \dfrac{3}{4}\\ \\4(3x)=3(25)\\ \\12x=75\\ \\x= \dfrac{75}{12}\\ \\ \\x= \dfrac{\not{75}}{\not{12}}\\ \\ \\x= \dfrac{25}{4}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question d):

$\dfrac{12}{7}*x= \dfrac{18}{35}\\ \\ \\ \dfrac{12}{7}x= \dfrac{18}{35}\\ \\35(12x)=7(18)\\ \\420x=126\\ \\x= \dfrac{126}{420}\\ \\ \\x= \dfrac{\not{126}}{\not{420}}\\ \\ \\x= \dfrac{3}{10}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question e):

$x\div{ \dfrac{8}{11} }= \dfrac{22}{7}\\ \\ \\ \dfrac{x}{1}\div{ \dfrac{8}{11} }= \dfrac{22}{7}\\ \\ \\ \dfrac{11*x}{8*1}= \dfrac{22}{7}\\ \\ \\ \dfrac{11x}{8}= \dfrac{22}{7}\\ \\7(11x)=8(22)\\ \\77x=176\\ \\x= \dfrac{176}{77}\\ \\ \\x= \dfrac{\not{176}}{\not{77}}\\ \\ \\x= \dfrac{16}{7}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question f):

$120\%\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{120}{100}\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{\not{120}}{\not{100}}\div{}x= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5}\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5}\div{ \dfrac{x}{1} }= \dfrac{14}{15}\\ \\ \\ \dfrac{1*6}{5*x}= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5x}= \dfrac{14}{15}\\ \\6(15)=14(5x)\\ \\90=70x\\ \\ \dfrac{90}{70}=x\\ \\ \\ \dfrac{\not{90}}{\not{70}}=x\\ \\ \\ \dfrac{9}{7}=x\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

$\textbf{HOPE\ THIS\ HELPS...!!}$

3 0

3 years ago

A plane left 30 minutes late than its schedule time and in order to reach the destination 1500 km away in time it had to increas

schepotkina [342]

Let x= the usual speed
1500/x would equal how long it usually took the plane to read the destination
1500/(x+100) would equal how long it would take the plane now
So $\frac{1500}{x} - \frac{1500}{x+100} = \frac{1}{2}$ because it would lose 30 minutes already
Simplify:
$\frac{1500(x+100)-1500x}{x(x+100)} = \frac{1}{2}$
$\frac{1500x+150000-1500x}{x^2+100x} = \frac{1}{2}$
$\frac{150000}{x^2+100x} = \frac{1}{2}$
$\frac{300000}{x^2+100x} =1$
$300000= x^{2} +100x

x^2+100x-300000=0

x^2+600x-500x-300000=0

x(x+600)-500(x+600)

(x-500)(x+600)

x=500, x \neq -600
$

The usual speed was 500 hm/hr

7 0

3 years ago

Factor f(x)=x2−8x+16<br><br> (A) (x−4)2<br> (B) (x+8)2<br> (C) (x−8)2<br> (D) (x+4)2

Fynjy0 [20]

Answer:

A

Step-by-step explanation:

(x-4)^2 = x^2 -4x -4x + (-4)*(-4)

= x^2-8x+16 as required

3 0

3 years ago

Describe how to draw a line that passes through the origin and has a slope of. -2/3

Ket [755]

You start from 0 and then you go to the left 2 units and then 3 down the y axis.

3 0

3 years ago