so i think its 97 degrees try that!
The population triples ( P × 3 ) every ten minutes...
So if ten minutes is reached there will be 1,200 bacteria.
Edited - missed the question
** The units for time should be in minutes.
P = 400 × 3^(t/10)
at t = 0 ; P = 400
at t = 10 ; P = 1,200
When P = 600
600 = 400 × 3^(t/10)
6/4 = 3^(t/10)
Log(3/2) = Log(3^(t/10))
power rule
Log(3/2) = (t/10) Log(3)
10 × Log(3/2)/Log(3) = t
3.69 minutes the population will be at 600 bacteria
Unites for time are in minutes.
The diagram can be redrawn as,
The value of x and y can be determined as,
![\begin{gathered} \tan C=\frac{AB}{BC} \\ \tan 45^{\circ}=\frac{x}{7\sqrt[]{2}} \\ x=7\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20C%3D%5Cfrac%7BAB%7D%7BBC%7D%20%5C%5C%20%5Ctan%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7Bx%7D%7B7%5Csqrt%5B%5D%7B2%7D%7D%20%5C%5C%20x%3D7%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \cos C=\frac{BC}{AC} \\ \cos 45^{\circ}=\frac{7\sqrt[]{2}}{y} \\ y=14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20C%3D%5Cfrac%7BBC%7D%7BAC%7D%20%5C%5C%20%5Ccos%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7B7%5Csqrt%5B%5D%7B2%7D%7D%7By%7D%20%5C%5C%20y%3D14%20%5Cend%7Bgathered%7D)
Thus, option (D) is the correct solution.
One scale factor equation is y=cx
y is the new factor (in this case, 60 or 75)
c is the scale factor (in this case, unknown)
x is the old factor (in this case, 24 or 30)
so: plug in the values
60=c(24) divide both sides by 24
c=2.5
you can check again with the other numbers
75=c(30) divide both sides by 30.
c= 2.5
your scale factor is 2.5
