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Murljashka [212]
2 years ago
15

Please answer this correctly

Mathematics
2 answers:
zloy xaker [14]2 years ago
7 0

Answer

51

Explanation

85/15=y/9

765=15y

51

Liono4ka [1.6K]2 years ago
3 0

Answer:

y = 51

Step-by-step explanation:

<u>These triangles are similar, so you can set up a proportion to solve for y:</u>

<u />\frac{85}{15} =\frac{y}{9}

<u>Cross multiply:</u>

<u />\frac{765}{15y}

<u>Divide 765 by 15:</u>

y = 51

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2 years ago
Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak
crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28

We can now calculate the probabilities:

P(0.47

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2

We can now calculate the probabilities:

P(0.47

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

8 0
3 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

7 0
2 years ago
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