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3 years ago

If cos 0 = 3/radical 22 and angle 0 is in Quadrant I, what is the exact value of tan 20 in

Mathematics

2 answers:

Sloan [31]3 years ago

6 0

Answer:

tan θ = (√13)/3

Step-by-step explanation:

cosθ = 3/√22 = adj/hyp

third side of triangle has dimension

c = √((√22)² - 3²) = √13

tan θ = opp/adj = (√13)/3

Greeley [361]3 years ago

6 0

−3

Step-by-step explanation:

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Calculate the volume of the prism shown below. 4 cm 2 cm 8 cm Volume: cm3

babunello [35]

Answer:

Step-by-step explanation:

4*2=8*8=64
ur welcome
64 cm3

4 0

2 years ago

El jefe de ventas comenta con tu padre que los 9.000 vehículos del mes pasado suponen unos buenos resultados, pero que este mes

Alja [10]

Answer:

900

Step-by-step explanation:

10% de 9000 es 900

Trabajando el 10% de 9000

Escribe 10% como 10100

Dado que, encontrar la fracción de un número es lo mismo que multiplicar la fracción por el número, tenemos

10100 de 9000 = 10100 × 9000

Por tanto, la respuesta es 900

Si está utilizando una calculadora, simplemente ingrese 10 ÷ 100 × 9000, lo que le dará 900 como respuesta.

6 0

3 years ago

-3/8x - 11 = 4 pls HELP me im getting no where right now.

VashaNatasha [74]

-3/8x - 11 = 4
-3/8x = 15 Add 11 to both sides
x = -40 Divide both sides by -3/8

7 0

4 years ago

For each day enter the number of hours worked. Use the format shown in Model 1 and answer in terms of a reduced fraction.

natulia [17]

It is often easiest to use "military time". That is, add 12 to all the afternoon numbers and do the subtraction in the usual way. Of course, 1 hour = 60 minutes, so 10 minutes = 10/60 hour = 1/6 hour.

Mon: 15:10 -8:00 = 7:10 = 7 1/6

Tue: 15:25 -8:05 = 7:20 = 7 1/3

Wed: 14:30 -8:00 = 6:30 = 6 1/2

Thur: 14:45 -7:55 = 7:(-10) = 6:50 = 6 5/6

Fri: 15:38 -7:58 = 8:(-20) = 7:40 = 7 2/3

_____
Some calculators have nice features for working with degrees, minutes, and seconds. In this context, degrees and hours are the same thing. That is, the base-60 arithmetic is the same whether you consider the numbers to be hours or degrees. Similarly, some calculators convert nicely between decimal fractions and mixed numbers. In short, a suitable calculator will almost do this math for you. (You just need to add 12 to all the numbers in the column on the right.)

3 0

3 years ago

Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral

Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

$l_{AB} = \sqrt{\left (6-4 \right )^{2}+\left (6-1 \right )^{2}} = \sqrt{29}$

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

$l_{BC} = \sqrt{\left (1-6 \right )^{2}+\left (4-6 \right )^{2}} = \sqrt{29}$

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

$l_{CD} = \sqrt{\left (-1-1 \right )^{2}+\left (-1-4 \right )^{2}} = \sqrt{29}$

The length of side DA, with D = (-1, -1) and A = (1,4) gives;

$l_{DA} = \sqrt{\left (4-(-1) \right )^{2}+\left (1-(-1) \right )^{2}} = \sqrt{29}$

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore;

$Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1$

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

$Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1$

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0

3 years ago