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3 years ago

Substitution Property of Equality: If AB = 20, then AB + CD

Mathematics

1 answer:

otez555 [7]3 years ago

5 0

Answer:

CD + 20

Step-by-step explanation:

If AB = 20, then AB + CD = 20 + CD

Answer: CD + 20

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Please answer this question

scZoUnD [109]

Domain in numerical order: {-7, -1, 0, 1}

Range in numerical order: {-1, 0, 1, 2, 7}

Which number is not part of the range of this relation? = -7

Hope this helps!

7 0

3 years ago

Find the value of |-4| - 5 · 2(-1 + 3).

vredina [299]

Use PEMDAS

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and |a| = a for a ≥ 0 or |a| = -a for a < 0.

|-4| - 5 · 2(-1 + 3) =-(-4) - 5 · 2(2) = 4 - 10(2) = 4 - 20 = -16

6 0

3 years ago

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Helpppp!! right answer only pleaseee

hodyreva [135]

Answer:

linear equation

Step-by-step explanation:

it's the only one that matches the description :)

5 0

3 years ago

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6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago

Over five different weeks, Irina tracked the hours she spent exercising and the hours she spent playing video games. What is the

madam [21]

Answer:

moderate negative correlation

6 0

3 years ago

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