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ankoles [38]
3 years ago
12

What is the radius of the circle shown below? x^2+y^2-2x+6y+9=0

Mathematics
1 answer:
aliina [53]3 years ago
8 0

Answer:

  1

Step-by-step explanation:

The graph below shows the radius to be 1.

__

If we rewrite the equation to standard form, we have ...

  (x^2 -2x +1) +(y^2 +6y +9) = -9 +1 +9

  (x -1)^2 +(y +3)^2 = 1

The square of the radius is 1, so the radius is 1.

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#7 is 69° because its vertical angle is 69°. Vertical angles are equal.
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Interior angles are already given except for #4. So, 180° - 69° - 69° = 42°
#3 is computed by 180° - 42° - 69° = 69°

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360° / 6 = 60°
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