3 years ago

What is the radius of the circle shown below? x^2+y^2-2x+6y+9=0

Mathematics

1 answer:

aliina [53]3 years ago

8 0

Answer:

Step-by-step explanation:

The graph below shows the radius to be 1.

If we rewrite the equation to standard form, we have ...

(x^2 -2x +1) +(y^2 +6y +9) = -9 +1 +9

(x -1)^2 +(y +3)^2 = 1

The square of the radius is 1, so the radius is 1.

You might be interested in

Which expression is equivalent to (4−3)−6? 418 43 4−18 4−9

Harlamova29_29 [7]

4-9 because (4-3)-6 is -5 and 4-9 is also -5

6 0

3 years ago

Congruent regular pentagons tessellate a plane. true or false?

MariettaO [177]

Check the tessellation picture below.

now, bear in mind that, you're asked on "regular pentagons", no irregular like the ones in the left-hand-side in the picture. Now, notice the ones in the right-hand-side, those are regular pentagons... well, do they tessellate?