Missing question: How many executives should be surveyed?
Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%
Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)
Where N = Sample population
N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554
Therefore, 554 executives should be surveyed to yield such results.
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Answer:
g ≈ 34.7 in
Step-by-step explanation:
The law of sines is useful for this:
f/sin(F) = g/sin(G)
Multiplying by sin(G), we have ...
g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)
g ≈ 34.7 in
Answer:
132−15+12
Step-by-step explanation:
To figure this out you first need to determine how many kg there are in 220 lbs. 1 lb equals 0.454 kg, so 220 lbs= 99.88 kg.
It states that a patient receives 7mcg per kg per minute, so the patient will receive 7 x 99.88=699.16 mcg per minute.
You need to convert this to a number of mcg per hour, so multiply the amount by 60 to get 41949.6 mcg per hour.
