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zmey [24]
3 years ago
10

Please everyone help me!

Mathematics
2 answers:
Harman [31]3 years ago
8 0

Answer:g=0 is not the solution

Step-byd-step explanation:

-1 1/2 is a negative number and 0 is not negative

Reika [66]3 years ago
8 0

Answer:

g=0

Step-by-step explanation:

happy to help ya :)

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For a party , Mr and Mrs. Kemper made 7.25. gallons of fruit punch.How many quarts of punch did they make.
lina2011 [118]
There are 29 quarts of fruit punch in 7.25 gallons of fruit punch.
4 0
3 years ago
Jake took out an interest-free loan of $3,011.70 from the bank to buy a car. He paid the bank $200.78 each month until it was pa
trasher [3.6K]
$200.78 multiplied by 15 equals <span>$3,011.70. So your answer is D)</span>
3 0
3 years ago
If p varies directly with T and p =105 when T=400.Find p when T =500
kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

when

T = 500

Substitute it into the above formula

That's

p =  \frac{21}{80}  \times 500

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

7 0
3 years ago
heather has divided $6300 between two invesments, one paying 9%, the other paying 4%. If the return on her investment is $372, h
Ganezh [65]
Assuming that the two investments are  X & Y
X + Y = 6300
X = 6300 - Y                                       (1)

9/100X + 4/100 Y = 372                       (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400

I hope this is helpful 



6 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
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