All categories

3 years ago

A’’ = B’’ = C’’ = D’’ = ???

Mathematics

1 answer:

mezya [45]3 years ago

6 0

Answer:

Step-by-step explanation:

b I did the test its correct

You might be interested in

6x-5y = 15 x=y+3 x= y=

Zina [86]

Answer: x = 0 y = –3

Step-by-step explanation:

We can solve this system by substitution.

use the second equation as a value for x.

Then substitute that value in place of x in the first equation and solve for y.

6x - 5y = 15 becomes

6(y + 3) - 5y = 15 Distribute 6 × parentheses

6y + 18 - 5y = 15 combine like terms

6y -5y + 18 = 15

y + 18 = 15 Subtract 18 from both sides.

y =15 -18

y = –3

Use this value for y in either equation to solve for x

6x - 5(-3) = 15

6x + 15 = 15 Subtract 15 from both sides, divide by 6 (seems silly!)

x = 0

OR in he second equation,

x = -3 + 3

Again, x = 0

6 0

2 years ago

An 11-inch by 8-inch piece of cardboard has squares cut out of the corners and is folded up to make an open-top box. If the volu

12345 [234]

Volume=14in^3

$\\ \sf{:}\implies (side)^3=14$

$\\ \sf{:}\implies side=\sqrt[3]{14}$

$\\ \sf{:}\implies side=2.5in$

Now

L=11in
B=8in

$\\ \sf{:}\implies Area=11(8)=88in^2$

Cut it into 10 parts as per question(Open side means five sides hence it will be 5×2=10)

$\\ \sf{:}\implies 88/10=8.8in$

Now divide by previous side

$\\ \sf{:}\implies \dfrac{8.8}{2.5}=3.52=3.5$

Option D

6 0

2 years ago

Indicate whether x and y show direct variation. 3 + y = 5x

dolphi86 [110]

Answer:

Let's understand the solution in detail.

Explanation:

Given: 5x = 3y

We can rearrange it as y = 5x / 3

Hence, we see that y ∝ x, and the equation is of the form y = kx, where k is the proportionality constant. This denotes that y varies directly with x.

Here k = 5 / 3.

Hence, the equation represents a direct variation, and the constant of variation is k = 5 / 3.

7 0

2 years ago

How do I solve for the missing lengths?

Advocard [28]

Answer:

Part 4) $ER=3\ units$

Part 5) $DF=9\sqrt{10}\ units$

Part 6) $DE=30\ units$

Step-by-step explanation:

Part 4) Find ER

we know that

In the right triangle ERF

Applying the Pythagorean Theorem

$EF^2=ER^2+RF^2$

substitute the given values

$(3\sqrt{10})^2=ER^2+9^2$

solve for ER

$ER^2=(3\sqrt{10})^2-9^2$

$ER^2=90-81\\ER^2=9\\ER=3\ units$

Part 5) Find DF

we know that

In the right triangle DRF

Applying the Pythagorean Theorem

$DF^2=DR^2+RF^2$

substitute the given values

$DF^2=27^2+9^2$

$DF^2=810\\DF=\sqrt{810}\ units$

simplify

$DF=9\sqrt{10}\ units$

Part 6) Find DE

we know that

$DE=DR+RE$ ----> by segment addition postulate

we have

$DR=27\ units\\RE=ER=3\ units$

substitute

$DE=27+3=30\ units$

3 0

3 years ago

ASAP am i correct?

avanturin [10]

Answer:

Its A and C. Since you need a reflection then a dilation to result in that image.

4 0

2 years ago

Read 2 more answers