9514 1404 393
Answer:
65 feet
Step-by-step explanation:
The problem involves finding the perimeter of a rectangle, then making adjustments to remove parts of the perimeter that aren't wanted.
The perimeter of a rectangle is given by the formula ...
P = 2(L+W)
For Aubrey's 12' × 8' room, the perimeter is ...
P = 2(12' +8') = 40'
This is the length of the border Aubrey needs at the ceiling.
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At "waist-high", we need to subtract the total width of all the windows and doors. That total is ...
3' + 4' + 3' + 5' = 15'
So, the waist-high border is 40' -15' = 25'.
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The total amount of border Aubrey needs is ...
ceiling border + waist-high border = 40' + 25' = 65'.
Aubrey needs 65 feet of border.
Answer:
46.7 mph
Step-by-step explanation:
The speed can be found by substituting the measured skid length for the variable in the formula.
v = √(20L)
v = √(20×109) = √2180 ≈ 46.7
The car was traveling at approximately 46.7 miles per hour.
Answer:
1. 42.0 meters
2. 16.8
3. 2.3
4. 24.7
5. a. 42.4 b. 10.7
6.4.01
Step-by-step explanation:
1. so by using soh cah toa: tan40 = x/50
multiply both sides by 50 : (tan40)50=x
simplify: 42.0m
2. same concept but different values: tan35=x/24
multiply 24 to both sides: (tan35)24=x
simplify : 16.8m
3. tano^-1 = 20/100
multiply both sides by tan^-1: the angle = tan^-1 (20/100)
Simplify: 2.3 degrees
4. cos o^-1 = 4.6/10
multiply both sides by cos^-1: the angle= cos^-1 (4.6/10)
simplify: 24.7
5. a. tan23= x/100
multiply 100 to both sides: x= 100(tan23)
simplify :42.4
b. you have to find the total height of the building with the antenna and then subtract the height of the building that you found in part a.
tan28=x/100
multiply 100 to both sides : (tan28)100=x
simplify 53.1
subtract the answer to part from 53.1:
53.1-42.4=10.7
Width=2/3 legnth
w=2/3l
width=30
w=30
30=2/3 legnth
multiply both sdies by 3/2 to clear fraction
90/2=6/6legnth
45=legnth
area=legnt times width
30 times 45=area=1350 feet^2