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Elan Coil [88]
3 years ago
15

Pls help !!!! I will mark as Brainiest

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:

Just subtract.

Step-by-step explanation:

luda_lava [24]3 years ago
6 0

Answer:

13 pounds

Step-by-step explanation:

205-192=13

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a photograph that measures 20 cm by 15 cm is enlarged so that its length becomes 28 cm. what does the width become?
NemiM [27]
The width becomes 21 centimeters hope this helps:)
8 0
3 years ago
Read 2 more answers
100x+300y=1.200<br> (2/3x+10)/100=(y+20)/300
AlexFokin [52]

Answer:

x= -4.284 and y= 1.432

Step-by-step explanation:

5 0
3 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
Roy is twice as old as Joan, and in 3 years the sum of their ages will be 21 years. Find their present ages.
Lisa [10]

Answer:

Roy is 10 years old at present and Joan is 5 years old at present

Step-by-step explanation:

Let

x----> Roy's age

y----> Joan's age

we know that

x=2y ----> equation A

(x+3)+(y+3)=21 ----> equation B

substitute equation A in equation B

(2y+3)+(y+3)=21

solve for y

3y+6=21

3y=21-6

3y=15

y=5 years

Find the value of x

x=2y  ----> x=2(5)=10 years

therefore

Roy is 10 years old at present

Joan is 5 years old at present

8 0
3 years ago
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\bf \textit{volume of a cylinder}=V=\pi r^2h\qquad &#10;\begin{cases}&#10;r=radius\\&#10;h=height\\&#10;-----------\\&#10;r=6\ in\\&#10;V=864\pi \ in^3&#10;\end{cases}&#10;\\\\\\&#10;V=\pi r^2h\implies 864\pi =\pi (6)^2h\impliedby \textit{solve for "h"}
6 0
3 years ago
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