All categories

3 years ago

Determine the rate of change of the graph

Mathematics

2 answers:

Hatshy [7]3 years ago

6 0

Answer:

4/5

Step-by-step explanation:

diamong [38]3 years ago

6 0

Answer:

0.6

Step-by-step explanation:

The rate of change is the slope m of the straight line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 20) and (x₂, y₂ ) = (20, 32) ← 2 points on the line

m = $\frac{32-20}{20-0}$ = $\frac{12}{20}$ = 0.6

You might be interested in

Please please help ‼️WILL MARK BRAINLIEST‼️ 10 Points

asambeis [7]

B is the right answer.

4 0

3 years ago

n=400 people under the age of 25 was asked whether they check social media sites right after they wake up. 42% check social medi

Aliun [14]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

p = 0.5

For the alternative hypothesis,

p < 0.5

Considering the population proportion, probability of success, p = 0.5

q = probability of failure = 1 - p

q = 1 - 0.5 = 0.5

Considering the sample,

P = 42/100 = 0.42

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

n = 400

z = (0.42 - 0.5)/√(0.5 × 0.5)/400 = - 3.2

Recall, population proportion, p = 0.5

We want the area to the left of 0.5 since the alternative hypothesis is lesser than 0.5. Therefore, from the normal distribution table, the probability of getting a proportion < 0.5 is 0.00069

So p value = 0.00069

Since alpha, 0.05 > than the p value, 0.00069, then we would reject the null hypothesis.

Therefore, there is significant evidence to conclude that that less than 50% of people under the age of 25 check social media sites right after they wake up.

7 0

3 years ago

Mitch needs four 10 gram samples of NaCl (Sodium Chloride) for an experiment. Mitch is using a balance that measures to 1/10 of

trapecia [35]

the complete question in the attached figure

The answer is the option A 9.9 grams
because the balance is accurate to the nearest 1/10 gram; thus, the highest level of accuracy appropriate to the limitations of the balance is 0.10 gram (1/10)