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3 years ago

6

Rafael is ordering an ice cream dessert. He must order a size, a flavor of ice cream, and a topping. There are 3 sizes, 3 flavor

s, and 1 topping to choose from. How many different ice cream desserts could he order?

1 answer:

Pavlova-9 [17]3 years ago

8 0

Answer:

9

Step-by-step explanation:

Multiply the number of sizes by flavors, the by toppings.

3*3*1

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nikklg [1K]

Answer:

x = 30

Step-by-step explanation:

30 + 2x = 90

2x = 60

x = 30

8 0

3 years ago

La dirección del Colegio Montes y los padres de familia están organizando un viaje cultural a Guanajuato para los alumnos de seg

notsponge [240]

Answer:

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the simultaneous equation,

The hotel has 15 single rooms and 32 double rooms.

Step-by-step explanation:

English Translation

The management of Colegio Montes and the parents are organizing a cultural trip to Guanajuato for second grade students and their teachers. Students will sleep in double rooms and teachers in singles. The hotel has double rooms (2 beds) and single rooms (1 bed), totaling 47 rooms and 79 beds. To confirm if they can be accommodated, they want to know how many rooms there are of each type. If "x" denotes single rooms and "y" denotes double rooms, Write the system of equations that represents the situation: Equation that represents the number of rooms (1) Equation that represents the number of beds (2)

Solution

The number of single rooms = x

The number of double rooms = y

The number of beds in single rooms = x

The number of beds in double rooms = 2y

Total number of rooms = 47

Total number of beds = 79

Sum of single and double rooms = Total number of rooms

x + y = 47 (eqn 1)

Sum of the beds in the single rooms and the beds in the double rooms = Total number of beds

x + 2y = 79 (eqn 2)

Writing the equations together

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the equations simultaneously,

x = 15, y = 32

Hence, the hotel has 15 single rooms and 32 double rooms.

Hope this Helps!!!

6 0

3 years ago

Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 229 wi

meriva

Answer:

A. 99% CI for p: 0.125 < p < 0.259

B. 99% CI for p: 0.807 < p < 0.911

C. 95% CI for p: 0.776 < p < 0.844

D. 95% CI using t-distribution: 23.7 < µ < 40.3

Step-by-step explanation:

A.

$p=\frac{x}{n} =\frac{44}{229} = 0.192139738$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.192139738(1-0.192139738)}{229} }$

$SE=\sqrt{\frac{0.155222059}{229} }$

SE = 0.026035

E = Margin of Error

E = z-value * SE = 2.58 * 0.026035

E = 0.067170516

Lower Limit = p - E = 0.192139738 - 0.067170516 = 0.125

Upper Limit = p + E = 0.192139738 + 0.067170516 = 0.259

99% CI for p: 0.125 < p < 0.259

B.

$p=\frac{x}{n} =\frac{256}{298} = 0.8590604$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.8590604(1-0.8590604)}{298} }$

$SE=\sqrt{\frac{0.121075629}{298} }$

SE = 0.020157

E = Margin of Error

E = z-value * SE = 2.58 * 0.020157

E = 0.052004

Lower Limit = p - E = 0.8590604 - 0.052004 = 0.807

Upper Limit = p + E = 0.8590604 + 0.052004 = 0.911

99% CI for p: 0.125 < p < 0.259

C.

$p=\frac{x}{n} =\frac{405}{500} = 0.81$

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Critical z-value = $z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.81(1-0.81)}{500} }$

$SE=\sqrt{\frac{0.1539}{500} }$

SE = 0.017544

E = Margin of Error

E = z-value * SE = 1.96 * 0.017544

E = 0.034387

Lower Limit = p - E = 0.81 - 0.034387 = 0.776

Upper Limit = p + E = 0.81 + 0.034387 = 0.844

95% CI for p: 0.776 < p < 0.844

D.

x = sample mean = 32

s = sample standard deviation = 13

n = sample size = 12

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Being the sample size less than 30, we use the statistical t.

df = degree of freedom = n - 1 = 12 - 1 = 11

Critical t-value = $t_{\alpha/2,df}=t_{0.05/2,11}=t_{0.025,11}=2.201$ (from t-table, two tails, df=11)

SE = standard error

$SE=\frac{s_{x} }{\sqrt{n} } =\frac{13 }{\sqrt{12} }=3.752777$

E = margin of error

E = t-value * SE = 2.201 * 3.752777 = 8.259862

Lower Limit = x - E = 32 - 8.259862 = 23.7

Upper Limit = x + E = 32 + 8.259862 = 40.3

95% CI using t-distribution: 23.7 < µ < 40.3

Hope this helps!

4 0

3 years ago

sara buys a sweater at a department store the sweater costs $30 the store is having a 25% off sale on everything in the store. e

tatuchka [14]

Answer:

$7.50

Step-by-step explanation:

Sara buys a sweater that costs $30

The store is having a 25% off sale.

To figure out what 25% is you do 25/100, which will give you 0.25,

Multiply 0.25 by $30

You should get $7.50.

3 0

3 years ago

Read 2 more answers

Add 13.7% to $45.50

Yuri [45]

i think first you must multiply $45.5 × 13.7/100

then you will get 6.2335

later you add 6.2335 to $45.5 and you will get $51.7335

i hope it is correct

8 0

3 years ago