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VLD [36.1K]
3 years ago
8

1/y = -3x/2+ 3 and rewrite it in the form of y = p/ q+x

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

1/y = -3x /2 + 3

mulytiply each term by 2y:-

2 = -3xy + 6y

y = 2 / -3( (x - 2)

y = -0.667 (-2 + x)

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What is the base five representation of The number 219
ICE Princess25 [194]

assuming 219_{10}

Then the column values for base five here are

5³  5²  5^{1}  5^{0}

We can get 1 × 5³ = 125 → 219 - 125 = 94

We can get 3 × 5² = 75 → 94 - 75 = 19

We can get 3 x 5^{1} → 19 - 15 = 4

and 4 = 4 × 5^{0}

Thus 219_{10} = 1334_{5}

As a check

(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219


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3 years ago
Name each polynomial by degree and number of terms of -7
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Answer: i couldn’t find the answer to this one either

Step-by-step explanation:

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2 years ago
Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

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Answer:

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3 years ago
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F(16) – f(0) when f (x) = 4x – 8?​
soldier1979 [14.2K]
The answer 56
Hope it helps
3 0
3 years ago
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