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VLD [36.1K]
3 years ago
8

1/y = -3x/2+ 3 and rewrite it in the form of y = p/ q+x

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

1/y = -3x /2 + 3

mulytiply each term by 2y:-

2 = -3xy + 6y

y = 2 / -3( (x - 2)

y = -0.667 (-2 + x)

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Graph two more functions in the same family for witch the parameter being changed is the y-intercept, b
Trava [24]

Answer:

The equation of line having slope m and y-intercept b is

 y = m x + b

The other two equations of line in the same family having intercepts p and q are,keeping the slope same i.e m , described in the question are

→ y= m x + p

→ y = m x  + q

As both the equation have same slope i.e m , so lines will be parallel, but their Y - intercept are different i.e distance from the origin where it cuts the y-axis are different i.e at a distance of p and q from origin.




3 0
3 years ago
Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the
adoni [48]

Answer:

45.55 meters

Step-by-step explanation:

I'm guessing she recorded above her height, right?

To find the height of the dam, use the tangent ratio:

tangentX=\frac{opposite}{adjacent}

The height of the dam is the side opposite the given angle, and this will represent x. The adjacent side (the hypotenuse is NEVER considered the adjacent side) is the distance from Scarlett to the dam. The angle of elevation is the angle of 26°. Insert the values:

tan26=\frac{x}{90}

Solve for x. Multiply both sides by 90:

90*(tan26)=90*(\frac{x}{90})\\\\90*tan26=x

Insert equation into a calculator:

x=90*tan26\\\\x=43.9

Now add Scarlett's height:

43.9+1.65=45.55

The dam is 45.55 meters tall.

<em>Finito</em> :D

6 0
3 years ago
NEED IT NOW PLEASE HELPPPP
frez [133]

Answer:

True.

Step-by-step explanation:

These angles are congruent because lines DE and BC are parallel.

3 0
3 years ago
Please help again, sorry for asking…
prohojiy [21]

Answer:

BC=6x+4= 6x4+4 = 28 is the correct answer

AB+BC=AC

4x+8+6x+4=52

10x+12=52

10x=40

X=4

4 0
2 years ago
Read 2 more answers
If f(x) = 2(x)^2 + 5 square root (x+2), complete the following statement (round your answer to the nearest hundredth): f(2) =
mojhsa [17]

f(x) = 2(x)^{2} +5 \sqrt{x+2}

f(2) = 2(2)^{2} + 5 \sqrt{(2)+2}

f(2) = 2(4) + 5\sqrt{4}

f(2) = 8 + 5(2)

f(2)= 8+10

f(2) = 18

3 0
3 years ago
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