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VLD [36.1K]
3 years ago
8

1/y = -3x/2+ 3 and rewrite it in the form of y = p/ q+x

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

1/y = -3x /2 + 3

mulytiply each term by 2y:-

2 = -3xy + 6y

y = 2 / -3( (x - 2)

y = -0.667 (-2 + x)

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3 0
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Lance is buying 2 pairs of pants that cost $15.25 each. There is a 8.5% sales tax.
loris [4]

Answer:

$33.09

Step-by-step explanation:

hope this helps :)

4 0
2 years ago
What will the factor tree look like with 25
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4 0
3 years ago
Yu and Elena each bought between 7 and 9 yards of ribbon. Yu
Mumz [18]

Given: Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon  Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon.

To find: Who can buy which ribbon

Solution:

Ribbon Sizes

1 2/3 = 5/3  yard

4/5  yard

3 1/2  = 7/2 Yard

Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon

Yu bought 3 pieces of ribbon

=> 3 * 5/3  = 5

  3 * 4/5  = 2.4

  3 * 7/2   = 10.5

Nailah  bought 5 pieces of ribbon

=> 5 * 5/3  = 8.33

   5 * 4/5  =  4

   5 * 7 /2   = 17.5

Elena bought 6 pieces of ribbon

=> 6 * 5/3  = 10

  6 * 4/5  = 4.8

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Only value between 7 & 9 is 5 * 5/3  = 8.33

hence Nailah only can buy 1 2/3 = 5/3  yard ribbon

or there is some mistake in the data

6 0
2 years ago
How do I add and subtract radicals with no like terms
liq [111]

Most real number arithmetic is pretty vacuous

\sqrt 2 + \sqrt 3 = \sqrt{2} + \sqrt{3}

That's about as good a way as possible to write this particular real number. But it's far from the only way.

(\sqrt 2 + \sqrt 3)^2 = \sqrt{2}^2 + 2\sqrt 2 \sqrt 3 + \sqrt{3}^2 = 5 + 2 \sqrt 6

so

\sqrt 2 + \sqrt 3 = \sqrt{5 + 2 \sqrt 6}

Sometimes you can factor something out and you have a common radical:

\sqrt{32} + \sqrt{128} = \sqrt{2^5} + \sqrt{2^7} = 4 \sqrt{2} + 8 \sqrt{2} = 12 \sqrt{2}

But most of them are vacuous,

3\sqrt{7} + 34 \sqrt{13} = 3\sqrt{7} + 34 \sqrt{13}


8 0
3 years ago
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