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VLD [36.1K]
3 years ago
8

1/y = -3x/2+ 3 and rewrite it in the form of y = p/ q+x

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

1/y = -3x /2 + 3

mulytiply each term by 2y:-

2 = -3xy + 6y

y = 2 / -3( (x - 2)

y = -0.667 (-2 + x)

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Use the drop-down menus to choose steps in order to correctly solve 4k−6=−2k−16−2 please help just need steps
luda_lava [24]
4k-6=-2k-16-2
4k-6=-2k-18
6k-6=-18
6k=-12
k=-2
3 0
2 years ago
What is the distance between the points (-3,5) and (3,-8) in the standard (x,y) coordinate plane?
zlopas [31]
The vertical distance is 5 + 8 = 13
the horizantal distance is 3 +3 = 6
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6 0
3 years ago
Read 2 more answers
F(x)=3x−4g(x)=−x2+2x−5h(x)=2x2+1j(x)=6x2−8xk(x)=3x2−x+7 Calculate (fh)(x).
elena-s [515]

Answer:

( f h ) (x)  = 6 x² - 1

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given<em> f(x)   =  3 x - 4</em>

         g (x)  = −x²+2 x−5

      <em>   h (x)  = 2 x² + 1</em>

         j (x)    = 6 x + 2 - 8 x

        K (x)   = 3 x² - x + 7

<u><em>Step(ii)</em></u>:-

<em>( f h ) (x) = f ( h (x)) = f ( 2 x² + 1 )</em>

                            =  3 (2 x² + 1 ) - 4

                            =  3 ((2 x² ) + 3 - 4

                           =   <em>6 x² - 1</em>

<u><em> Final answer:</em></u>-

∴ <em> ( f h ) (x)  = 6 x² - 1</em>

3 0
2 years ago
Define geometric relationship​
blagie [28]

Answer:

Geometric relationships control the orientation of an element with respect to another element or reference plane. For example, you can define a tangent relationship between a line and an arc. ... For example, a connect relationship and a tangent relationship can be used where an arc meets a line. (make me brainliest)

7 0
3 years ago
Tatiana is practicing shooting. The coordinates (in m) of the barrel of her gun and the target are (5, 3, 1) and (38, 41, 3). Wh
saul85 [17]

Answer:

d=\sqrt{2,537}\ m   or  d=50.37\ m

Step-by-step explanation:

we know that

the formula to calculate the distance between two points in three dimensions is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}+(z2-z1)^{2}}

Let

A(5,3,1)  -----> coordinates of the barrel of her gun

B(38,41,3)  -----> coordinates of the target

substitute the values

d=\sqrt{(41-3)^{2}+(38-5)^{2}+(3-1)^{2}}

d=\sqrt{(38)^{2}+(33)^{2}+(2)^{2}}

d=\sqrt{1,444+1,089+4}

d=\sqrt{2,537}\ m

d=50.37\ m

7 0
3 years ago
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