All categories

3 years ago

- 3/5 x = 15 Solve this question please

Mathematics

2 answers:

Triss [41]3 years ago

8 0

Answer:

3/5x = 15

multiply both sides by 5

This cancels out denominator of fraction =

3x = 75

x = 25

fomenos3 years ago

8 0

Answer:

3/5 x=15

x= 5×5

x= 25

Step-by-step explanation:

You might be interested in

Suppose y varies directly with x. Write a direct variation equation that relates x and y.

timama [110]

$\huge\mathfrak\purple{Answer:-}$

★ Option (A) y = -5x is the right answer.

<h3>I hope this helps! :)</h3>

8 0

3 years ago

There is an attachment below...I need this answers ASAP with work...please write it on a piece of paper if you can and send a ph

slamgirl [31]

I think task 1 is B

Hope this helps

Don't forget to rate and thanks me

7 0

3 years ago

Read 2 more answers

The team's combined score was 0. What was Travis's score

Pavlova-9 [17]

Answer:

Sorry but we need more info.

Step-by-step explanation:

8 0

3 years ago

2 tan 30° II 1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

Help with 1 and 2 polygons

Taya2010 [7]

#1 is a pentagon.
It's regular, because all the sides are the same length.

#2 is a hexagon.
It's not regular, because the sides don't all have the same length.

3 0

3 years ago

Read 2 more answers