3 years ago

-9 · (-8) = O 72 00 o 00 O-72

Mathematics

1 answer:

Masja [62]3 years ago

6 0

Answer:

Step-by-step explanation:

Hope it helps

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Scientists were studying a rare species of parrot they went to fourth in the year 2010 and found there were 608 pairs in the for

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6926 pairs in 2016.

Step-by-step explanation:

The number of pairs in t years after 2010 is modeled by the following function:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the number of pairs in 2010 and r is the growth rate, as a decimal.

608 pairs in 2010

This means that $P(0) = 608$

$P(t) = P(0)(1+r)^{t}$

$P(t) = 608(1+r)^{t}$

4617 pairs five year later.

So P(5) = 4617. We use this to find 1 + r.

$P(t) = 608(1+r)^{t}$

$4617 = 608(1+r)^{5}$

$(1+r)^{5} = \frac{4617}{608}$

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$1 + r = 1.5$

$P(t) = 608(1.5)^{t}$

How many pairs in 2016?

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$P(6) = 608(1.5)^{6} = 6926$

6926 pairs in 2016.

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3 years ago