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3 years ago

9

Plz help me I will mark u brainiest

1 answer:

Likurg_2 [28]3 years ago

5 0

Answer:

quadrant one

Hope this helps

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Find the measure of each angle I’ll mark the brainiest :)

laila [671]

Answer:

9. 70° 10. 90° 11. 110°

Step-by-step explanation:

12. 25°

13. 95°

14. 20°

3 0

3 years ago

The square of a number minus 14

sp2606 [1]

Answer:

-196

explain: √3.742 - 14 = -196

4 0

2 years ago

Which of the following functions has the largest value when x = 4?

kotegsom [21]

Answer:The function v(x) has the largest value when x = 4.
Solution:
x=4;
e(4) = 4^2 + 6×4 + 21=16+24+21=61
m(4) = 8×4=32
v(4) = 31×4=124
v(4)>e(4)>m(4)
Therefore,The function v(x) has the largest value when x = 4.

7 0

3 years ago

1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn

alisha [4.7K]

Answer and explanation:

Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.

To find : Determine each of the following,

a) $(A\cap B)\cap C$

b) $(A\cup B)\cap (A\cup C)$

c) $A - (B\cup C)$

d) $(A-C) (C-A)$

Solution :

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.

The intersection of two sets is a new set that contains all of the elements that are in both sets.

a) $(A\cap B)\cap C$

$A\cap B=\{1,4,5\}$

Then, $(A\cap B)\cap C=\{4\}$

b) $(A\cup B)\cap (A\cup C)$

$A\cup B=\{1,2,3,4,5,7,8,9\}$

$A\cup C=\{1,2,3,4,5,7,9\}$

$(A\cup B)\cap (A\cup C)=\{1,2,3,4,5,7,9\}$

c) $A - (B\cup C)$

$B\cup C=\{1,2,4,5,6,7,8,9\}$

$A - (B\cup C)=\{3\}$

d) $(A-C) (C-A)$

$A-C=\{1,3,5\}$

$C-A=\{6,7,9\}$

$(A-C) (C-A)=\{1,3,5\}\times\{6,7,9\}$

$(A-C) (C-A)=\{(1,6),(1,7),(1,9),(3,6),(3,7),(3,9),(5,6),(5,7),(5,9)\}$

5 0

2 years ago

Please help!!! Brainliest for whoever is right! What is the sum of the rational expressions below?

fenix001 [56]

Answer:

<h2> $\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2} + 3x}$ </h2>

Step-by-step explanation:

$\frac{2x + 3}{3x} + \frac{x}{ x + 1}$

Write all the numerators above the least common denominator

$\frac{(x + 1)(2x + 3) + 3 {x}^{2} }{3x(x + 1)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2} }{3x(x + 1)}$

Distribute 3x through the parentheses

$\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2} }{3 {x}^{2} + 3x}$

Collect like terms $=\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2} + 3 x}$

Hope this helps...

Good luck on your assignment...

6 0

3 years ago