Amount of fuel in the tank before the story begins . . . . . zero.

Total amount poured in . . . . . 3/4 gallon.

Total amount burned:
   on Friday . . . . . 1/4 gallon
   on Sunday . . . . 1/4 gallon
   Total used . . 1/2 gallon .

Amount remaining in the tank on Monday:

   (3/4 gallon in) - (1/2 gallon burned) = 1/4 gallon left.
      ==> NOT empty

The tank would have been empty on Monday IF Becky
had poured in only 1/2 gallon, instead of 3/4 of a gallon
before the first flakes began to fly.

8 0

3 years ago

Miss Robin distributed a bag of skittles to her students she gave each student five skittles then ate the 8 that remained in the

Damm [24]

Answer:

Step-by-step explanation:

First, subtract 8 from 143 which would give you 135. You then divide 135 by 5 and you get 27

8 0

2 years ago

The graph of y=x^3 is transformed as shown in the graph below. With. Equation represents the transformed function

taurus [48]

Answer: y' = (-x)^3 - 4

Step-by-step explanation:

The graph y = f(x) = x^3 passes trough the point (0,0)

because when x = 0

f(0) = y = 0^3 = 0

in the graph of the image, we can see that the graph intersects the y-axis in the point (0, -4)

This means that we have a vertical displacement of 4 units downwards.

When we have a graph y = f(x), a vertical translation of A units can be written as

y' = f(x) + A

If A is positive, the displacement is upwards, if A is negative, the displacement is downwards.

So if the displacement is of 4 units down, A = -4

We also have that when x is negative, the value of y is positive.

But in our original function, we have that for x = -1, y = (-1)^3 = -1

so in our original function, when x is negative also does y.

Then we also did a reflection around the y-axis, this means that we now evaluate the function in -x instead of x.

So the equation of the graph is:

y' = (-x)^3 - 4

8 0

3 years ago

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and

defon

The expression that can be used to approximate the expression below is $log_a x = \frac{log_{b}a}{log_{b}x}$

Given the logarithmic function expressed as $log_a x$ , we need the log expression that is equivalent to the given expression.

To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;

$log_a x = \frac{log_{10}a}{log_{10}x}$

This is similar to the option c where the base of "b" was used as $log_a x = \frac{log_{b}a}{log_{b}x}$

Learn more on law of logarithms here: brainly.com/question/11587706

3 0

2 years ago