3 years ago

13) Bubba's Pizza-o-rama is setting up a buffet for a banquet.

Mathematics

1 answer:

liubo4ka [24]3 years ago

8 0

I think it’s 3 ways

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How to simplify the expression x+3+5x

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Combine 5x and x and that makes 6x+3

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The 12 members in Dante's hiking club shared 176 ounces of trail mix equally. How many ounces of trail mix did each member reciv

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Frank has devised a formula for his catering business that calculates the number of meat balls he needs to prepare the formula i

ira [324]

Answer:

96 meatballs are required

Step-by-step explanation:

We know that the formula for he catering business is

$m=4a+2c$

Where

c= the number of children, m=the number of meat balls, a= the number of adults

So if $c = 8$ and $a = 20$ then

$m = 4(20) + 2(8)$

$m = 80 + 16$

$m = 96$

Finally 96 meatballs are required for the party

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3 years ago

Consider the ratio 3:5.can you create an equivalent ratio by adding the same number to each quantity in the ratio?Explain

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2 years ago

Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.

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Answer:

The answer is " $cirtical\ points \ (x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$ "

Step-by-step explanation:

Given:

$g(x) = (x-e)^3e^{-(x-e)}$

Find critical points:

$g(x) = (x-e)^3e^{(e-x)}$

differentiate the value with respect of x:

$\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r} \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]$

critical points $g'(x)=0$

$\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3$

So,

The critical points of $(x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$

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3 years ago