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Alex
3 years ago
7

Which equation can be used to solve for c?​

Mathematics
1 answer:
Lynna [10]3 years ago
5 0

Answer:

The second option

Step-by-step explanation:

cos35=5/c

5/c=cos35/1

cos35(c)=5

c=5/cos35

Therefore, the second option.

I hope this helped and have a good rest of your day!

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Select the equivalent expression
slava [35]
Answer: c
hope this helps!
7 0
3 years ago
What is the result if 3x-9 is evaluated when x = -5?​
Anton [14]

Answer:

Step-by-step explanation:

I wonder if it is the minus that is causing the problem?

Let x = - 5

3*(-5) - 9

-15 - 9

This is a money question. If you are 15 dollars in debt and you spend another 9, where are you? (In the company of the American government. They do this all the time).

- 15 - 9 = - 24

5 0
3 years ago
1: In order to solve the inequality -1/4 x > 8, which of the following steps must be done?
pogonyaev

Answer:

Step-by-step explanation:

-1/4x>8

x>8/(-1/4)

x>(8/1)(-4/1)

x>-32/1

x>-32

x<-32

The answer is D.

--------------------------

-3t+7>=9

-3t>=9-7

-3t>=2

t>=2/-3

t>=-2/3

t<=-2/3

The answer is A.

3 0
3 years ago
Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i
sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

x = 5

4 0
3 years ago
Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).
Mashcka [7]

Answer:

X = 0,  π/2 in the interval  [0, 2pi).

Step-by-step explanation:

Use the auxiliary angle method:

R sin(x + a)  = Rsin x cos a + Rcos x sin a = 1

                        sin x         +    cos x             = 1

Comparing coefficients:

R cos a = 1 and R sin a =  1, so

tan a = R sin a / R cos a  = 1

So a = π/4 radians.

Also  R^2(sin^2 a + cos^2 a) =  1^2 + 1^2 = 2

Therefore R = √2.

So √2 sin (x +π/4 = 1

sin x + π/4 = 1/√2

x  + π/4 = π/4

x = 0 radians

Also

x = 0 +  π/2 = π/2.

8 0
3 years ago
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