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ankoles [38]
4 years ago
13

Subtract the fractions and simplify the answer 7 8/9-5 3/5

Mathematics
1 answer:
weeeeeb [17]4 years ago
4 0
One way in which to do this problem would involve subtracting 5 from 7 (result:  2) and then subtracting 3/5 from 8/9.
To subtract 3/5 from 8/9, you'd need to find the lowest common denominator (LCD) of 3/5 and 8/9, convert both fractions to have this LCD, and then subtract.

The LCD is (5)(9)=45.  Then 8/9 and 3/5 become 40/45 and 27/45.

Subtracting 27/45 from 40/45 results in the fraction 13/45.
Then the full solution is  2 13/45.

You could also do this problem by converting  7 8/9    and   5 3/5 into improper fractions:

71/9 - 28/5.  Again, the LCD is 45.  Can you rewrite both fractions with 45 as the common denominator and then perform the subtraction?
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3 years ago
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A rectangular sheet of paper is 25/2cm long and 32/3 cm wide. Find its perimeter. *​
Zina [86]

Answer:

46.3cm

Step-by-step explanation:

  • perimeter is length around shape
  • 25/2 multiply by 2 becoz it's got two equal sides
  • 32/3 multiply by two for the other equal sides
  • add answers together to give you
  • 46.3cm
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Y=2x^2+12x+14 in vertex form
balandron [24]

Answer:

y = 2(x + 3)² - 4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Using the method of completing the square

y = 2x² + 12x + 14 ← factor out 2 from the first 2 terms

  = 2(x² + 6x) + 14

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + 6x

y = 2(x² + 2(3)x + 9 - 9 ) + 14

  = 2(x + 3)² - 18 + 14

  = 2(x + 3)² - 4 ← in vertex form

4 0
3 years ago
4) Use the distance formula to find the length of segment BC.
gogolik [260]

Answer:

5

Step-by-step explanation:

d= √(5-1)^2+(1-4)^2

d= √4^2+(-3)^2

d= √16+9

d=√25

d=5

8 0
3 years ago
Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?
Sveta_85 [38]
^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\  \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right


Answer: system nr 4.
7 0
3 years ago
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