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3 years ago

Find the measure of the arc indicated. Assume that lines which appear tangent are tangent.

Mathematics

1 answer:

Aleksandr [31]3 years ago

4 0

Answer:

Minor Arc AC = 360 - 235 = 125°

$mABC = \frac{Major \ arc - Minor \ arc}{2} = \frac{235 - 125}{2} = \frac{110}{2} = 55$

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3 years ago

A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.

finlep [7]

Answer:

Part a) The elevation of the road is $6\°$

Part b) The rise is $0.2\ km$

Step-by-step explanation:

Part a) What is the elevation of the road to the nearest degree?

Let

y-----> the rise of the road ( vertical distance)

x ----> the run of the road (horizontal distance)

we have

y/x=1/10

we know that

The ratio y/x is equal to the tangent of the angle of the elevation of the road

Let

$\theta$ ----> angle of the elevation of the road

$tan(\theta)=y/x$

$tan(\theta)=1/10$

$\theta=arctan(1/10)=6\°$

Part b) If the road is two km long, how much does it rise?

using proportion

$1/10=y/2$

$y=2/10=0.2\ km$

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3 years ago

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4 years ago

Write the equation of the line that passes through (-2,0) and (0, -7)

MakcuM [25]

Answer:

Step-by-step explanation:

(-2,0) (0,-7) y2-y1

-----------------

x2-x1

-7-0= -7

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y= -7/2x+b to find b u plug in one pair of coordinates for example (-2,0)

and use inverse properties to find b

0 = -7/2(-2) + b

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4 years ago

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lianna [129]

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4 years ago

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