Answer:
The first option
Step-by-step explanation:
2/9 x + 3 > 4 5/9
2/9x > 4 5/9 - 3
2/9x > 14/9
x > 14/9 ÷ 2/9
x > 7
Answer:
the answer would be 14-16=-2
Step-by-step explanation:
first u look where the first long arrow goes on this problem then you follow the second arrow which stops at 6 then u count how much until negative 2. but how I did it is the form 14 how much to 0 which is 14 the I count how many until I get to -2 and there's the answer
Answer:
(a)
and 
(b) The sample variance is
and the sample standard deviation is 
Step-by-step explanation:
(a)
The sum of these 17 sample observations is

and the sum of their squares is

(b)
The sample variance, denoted by
, is given by

where 
Applying the above formula we get that


The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

Applying the above formula we get that
