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4 years ago

Find the angle measures for this isosceles triangle.

Mathematics

1 answer:

nasty-shy [4]4 years ago

6 0

Answer:

Step-by-step explanation:

3p + 6p + 6p = 180 deg

15p = 180

p = 12

thus,

36 deg, 72 deg, 72 deg (ANS)

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A rectangular piece of wood is 12 centimeters longer than it is wide. A strip 1 centimeter wide is cut off all around. This decr

denis-greek [22]

Answer:

Length 37 cm, width 25 cm.

Step-by-step explanation:

Let the original dimensions be length x and width x - 12 cms.

The new dimensions will be length (x - 2) and width (x - 12 - 2) = x-14 cm.

So , from the areas, we have:

x(x - 12) - (x - 2)(x - 14) = 120

x^2 - 12x - (x^2 - 16x + 28) = 120

-12x + 16x - 28 = 120

4x = 148

x = 37 cms

So the length was 37 cm and the width was 37-12 = 25 cm.

7 0

4 years ago

Find the distance between 2 and -2 A. -6 B -4 C. 0 D. 4

tangare [24]

Answer:

b) -4

Step-by-step explanation:

Well your at 2 and going to -2 so on a number line you be going back or left.

Going two left gets you to zero and going two more get you -2. So in total you went back four and that be represented as -4.

5 0

3 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

3 years ago

Which equation has no solution?

VARVARA [1.3K]

3x-5=4y-6 is the answer

8 0

3 years ago

Can u please answer this question ASAP

REY [17]

Set both y’s equal to each other.

2x-1 = 3x+4
2x-3x = 4-(-1)
-x = 5
x = -5

Plug x = -5 into any of the given equation. I will use the first one as an example.

y = 2x-1
y = 2(-5)-1
y = -11

Answer: (-5, -11)

4 0

3 years ago