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3 years ago

If each square on the grid represents 5 square feet what is the approximate area of the fish pond

Mathematics

2 answers:

inna [77]3 years ago

7 0

165 square feet, approximately.

wlad13 [49]3 years ago

7 0

165 square feet is the correct answer. Each half square is equal to 25, so if you add 50 for each full tile and 25 for each half tile, you should reach the answer of 165 square feet.

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Write a rule that tell how to use mental math to find the product 30,000 x 50,000

tensa zangetsu [6.8K]

Answer:Step 1. Think of the basic fact. Multiply. 6 2 12

Step 2- Count the number of zeros in the factors.

60 has 1 zero and

20 has 1 zero.

Step 3- Write that number of zeros to the right of The answer is 1,200.

the basic-fact product.

<h2>hope this helps have a awesome night/day❤️✨</h2>

Step-by-step explanation:

7 0

3 years ago

The perimeter of this figure is 42.5 cm. Find the area of this figure.

11111nata11111 [884]

The picture in the attached figure

let
AB=x

we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm

area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²

area of the figure=54.1875+18.0625-----> 72.25 cm²

the answer is
72.25 cm²

3 0

3 years ago

#15: A shipment to a warehouse consists of 2,000 watchbands. The

Ad libitum [116K]

2 out of 50 are defective.

Divide 2 by 50: 2/50 = 0.04

Now multiply the total quantity by that:

2000 x 0.04 = 80

80 are likely to be defective.

6 0

2 years ago

From 1980 to 1990, the consumer price index (CPI) increased from 82.4 to 130.7. If a gallon of apple juice cost $0.95 in 1980 an

ryzh [129]

Answer: C $1.51

To solve this, start with a proportion. Put the CPI numbers on the left and the apple juice prices on the right.

You will have:

82.4/130.7 = 0.95/x

Cross multiply to solve and you will get the price of the juice is $1.51.

4 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago