For this case we have the following inequality:
2 ≥ 4 - v
The first thing we must do in this case is to clear the value of v.
We have then:
v ≥ 4 - 2
v ≥ 2
Therefore, the solution set is given by:
[2, inf)
Answer:
See attached image.
Answer: x = 22
Explanation:
1) Corresponding sides and correspoding angles of congruent triangles are equal.
2) When you name two congruent triangles the order of the vertices signal which sides and angles are congruents.
That triangle ABC is congruent to triangle DEF means that these are the corresponding parts, which are congruent to each other:
- ∠A and ∠D are congruent
- ∠B and ∠ E are congruent
- ∠C and ∠F are congruent
- Segment AB and segment DE are congruent
- Segment BC and segment EF are congruent
- Segment AC and segment DF are congruent
In the figures, it is given that the segment DF measures (1/2)x - 1 and the corresponding segment AC measures 10 units.
Hence, you set this equation: (1/2)x - 1 = 10
Solving for x:
- (1/2)x = 10 + 1
- (1/2)x = 11
- x = 2(11)
- x = 22 ← answer
Answer:
16
Step-by-step explanation:
as an expression: (15 - 6) + (-2 + 9)
simplify quantities: (9) + (7)
sum: 16
:D
Answer:
Step-by-step explanation:
AD and EH are parallel lines
Angle CBD = Angle CFH = x (corresponding angles)
x + 2x = 180 (angles on a straight line)
3x = 180
x = 60
Angle GFH = 120
Angle CBD = 60
Answer: 0.0221
Step-by-step explanation:
We know that the formula to find the standard deviation of the sample proportion is :

, where p = proportion of success.
n= sample size.
As per given , we have
p=0.58
n= 500
Then, the standard deviation of the sample proportion in this situation would be :

Hence, the standard deviation of the sample proportion in this situation is 0.0221 .