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Basile [38]
3 years ago
11

Find the zeros of the function f(x)=x2+2x-3

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Answer:

x = -1 and x = 3

Step-by-step explanation:

f(x)= x^2-2x-3

f(x) = (x + 1) (x - 3)

Therefore, x = -1 and x = 3

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using the Cosine rule in ΔSTU

let t = SU, s = TU and u = ST, then

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3 years ago
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6 0
3 years ago
Major help please !!!!!!!
ExtremeBDS [4]

3 5/9 divided by -2 2/3

change the mixed numbers to improper fractions

3 5/9 = (9*3+5)/9 = 32/9

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4 0
3 years ago
Find the t-value such that the area in the right tail is 0.005 with 28 degrees of freedom.
klasskru [66]

Answer:

t = 3.673900

Step-by-step explanation:

Given

df = 28 -- degree of freedom

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Required

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P(T>t) = 0.005

To solve further, we make use of the attached the student's t distribution table.

From the attached table,

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4 0
3 years ago
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