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1 year ago

Complete the table in your scratch paper and answer the following question below.

Mathematics

1 answer:

nalin [4]1 year ago

3 0

Total frequency = 56.

Total fx = 1717

midpoint of 45-49 = 47

Mean of the data = 30.7

Median of the data = 31.3

Mode of the data = 32.5

A measure of central tendency (also referred to as measures of centre or central location) is a summary measure that attempts to describe a whole set of data with a single value that represents the middle or centre of its distribution.

Here, total frequency ∑f = 5+7+9+11+8+7+5+4

= 56 (option B)

Total fx or ∑fx = 12X4 + 17X5 + 22X7 + 27X8 + 32X11 + 37X9 + 42X7+ 47X5

= 48 + 85 + 154 + 216 + 352 + 333 + 294 + 235

= 1717 (option B)

The midpoint of the score 45-49 = (45 + 49)/2

= 47 (option B)

Mean of the data = ∑fx/ ∑f

= 1717 / 56

= 30.7 (option D)

Median of the data = 31.3 (option A)

Mode of the data = 32.5 (option B)

Thus, Total frequency = 56.

Total fx = 1717

midpoint of 45-49 = 47

Mean of the data = 30.7

Median of the data = 31.3

Mode of the data = 32.5

Learn more about Central Tendency from:

brainly.com/question/13606190

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Answer:

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Step-by-step explanation:

Considering the slope formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

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Here:

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3 years ago

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pochemuha

Answer:

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Step-by-step explanation:

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A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th

myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

$h+c=593\\c=h-57$

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

$h+h-57=593\\2h-57=593\\2h=650\\h=325$

Therefore, the number of hamburgers sold on Thursday were 325.

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