Given: AD∥BC and AB∥CD
Prove: AD≅BC and AB≅CD
2 answers:
I’m guessing SSS because they are both sharing the side in the middle
Answer:
BC || AD and AB || CD (given)
∠BCA ≅ ∠DAC 2. As alt.interior angles with parallel lines
∠BAC ≅ ∠DCA 3. As alt.interior angles with parallel lines
AC ≅ AC (identity)
△ABC ≅ △CDA (ASA)
AB = CD (CPCT C)
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