Answer:= - sin( square root 8 over 3)sin(1/4)
Step-by-step explanation:
So I did (square root 8/3)(square root 15/4)+sin(1/4)cos(-1/3) divide that by (-1/3)(square root 15 over 4) - sin( square root 8 over 3)sin(1/4)
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
4232 divided by 18 equals 235.1
Answer:
I think I explained the circle one before so I'll explain the left question because I wanted some points.
here,
area of circle is πr² which is given= 12 π cm²
so πr²= 12π
r= 2√3
d= 2r= 4√3
AB is diameter so AB= 4√3
Answer:
y=1/3x_1/5=1/3×15=5_1/5×15=3. 5_3=2
