1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
taurus [48]
3 years ago
8

1

Mathematics
1 answer:
jeka943 years ago
8 0

Answer:

g(x)

because it is a quadratic equation it is mirrored the other one isn’t even a function

You might be interested in
If I have a 40 % and my teacher puts in 3 100% what’s my grade ?
Black_prince [1.1K]
It would be an A if i'm correct.
6 0
3 years ago
Read 2 more answers
A swearer cost $20 but the price was reduced to $ 12 what was the price after the price was reduced
bixtya [17]

Answer:

$20-$12=

Step-by-step explanation:  

20-12=8

5 0
3 years ago
Estimate the area of Alberta in square miles. Show your reasoning
ella [17]

Answer:  About 278,250\ mi^2

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid  can be calcualted with the formula:

A_t=\frac{h}{2}(B+b)

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

 A_r=lw

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

A=\frac{h}{2}(B+b)+lw

Substituting vallues, you get:

A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2

Therefore, the area of of Alberta is about 278,250\ mi^2.

5 0
3 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
Which value is the 10th term in the sequence:-62,-47,-32,-17,-2?
balu736 [363]
The answer is 13
Sure!!!
5 0
3 years ago
Other questions:
  • What is 4 divided 643???
    11·1 answer
  • Ben has square garden that has sides measuring 12 feet. Ben want to increase every side of his garden by x, feet in order to pla
    5·1 answer
  • What is the place value of 1 in 5,678.321
    15·1 answer
  • Tina is planning to fence in an area for her dog. She wants to create a rectangular area of 1,600 square feet for her pet and ca
    8·1 answer
  • Which defines a circle?
    8·2 answers
  • PLZ I NEED URGENT HELP
    11·1 answer
  • Assume the
    12·1 answer
  • Georgie is 40 years old <br> Her friends summer is 7/8 of her age <br> How old is summer?
    15·2 answers
  • Find the slope and y-intercept of the line in each graph.
    6·1 answer
  • Write the expression 8⋅ y ⋅ y ⋅ y ⋅ y using exponents.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!