Which inequality is represented by the graph?
1 answer:
Answer:
B: 4/5x -2y ≥ 3
Step-by-step explanation:
The first thing I always look for is the y-intercept which in this case is around -1.5 (-). That will be your constant (b) in y = mx + b. Then calculate the slope which will be your m in the equation. Visually, I would estimate it is around
. So now, your equation is y =
x -1
. Next we want to figure out what the inequality will be. The shaded part is underneath the line, which means that y must be less than where the line is. Therefore the inequality will be y ≤
x -1
.
Now in this question, the answers available are not in this form. The next step would be to multiply every part of the inequality by 2 (it is essential that all parts are multiplied) so that you get 2y ≤ x -3. The last step is to rearrange the inequality so that it matches the answers on the question.
3 ≤ x - 2y
x - 2y ≥ 3
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Answer:
43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
Step-by-step explanation:
To solve this problem, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
Find the probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
This is 1 subtracted by the pvalue of Z when X = 75.75. So
has a pvalue of 0.5675.
1 - 0.5675 = 0.4325
43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) =
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab