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irga5000 [103]
3 years ago
5

Mary took 8 tests in science and received the following scores: 87,60,76,92,63,91,88,75

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answers:

  • mean = 79
  • mode = none
  • median = 81.5

=================================================

Explanation:

To get the mean, you add up the numbers and then divide by n = 8, since there are 8 scores

Adding the scores gets us: 87+60+76+92+63+91+88+75 = 632

Divide that over n = 8 to get 632/n = 632/8 = 79

The mean is 79

You have the correct answer. Nice work.

---------------

The mode is the most frequent value.

In this data set, we don't have any repeated values. Each unique number is listed one time only. So that tells us we don't have a mode here.

---------------

To get the median, we need to sort the items from smallest to largest

{87,60,76,92,63,91,88,75} sorts to {60,63,75,76,87,88,91,92}

Because we have n = 8 values, which is an even number, this tells us that the median is between slot n/2 = 8/2 = 4 and slot 5

The values 76,87 are in slots four and five in that order. Add them up and divide by 2:  (76+87)/2 = 163/2 = 81.5 is the median

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Step-by-step explanation:

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What is the solution to the expression 12÷4+(1/3)²⋅9⋅3 ?
krok68 [10]

Answer:

6

Step-by-step explanation:

STEP

1

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           1

Simplify   —

           3

The equation at the end of step

1

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 12       1

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STEP

2

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Equation at the end of step

2

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 12       1

 —— +  ((—— • 9) • 3)

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3

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Canceling Out:

3.1      Canceling out  32 as it appears on both sides of the fraction line

Equation at the end of step

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 12    

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STEP

4

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Simplify   —

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Pulling out like terms

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2 years ago
Read 2 more answers
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Ede4ka [16]

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7 0
3 years ago
A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu
Lina20 [59]

Answer:

a) 0.5

b) 0.5

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d) 1

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Step-by-step explanation:

a)

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

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P(A)=3/6=1/2=0.5

b)

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

c)

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

d)

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

e)

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

f)

A-C={1,3,5}-{1,3,9,11}={5}

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P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0
3 years ago
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