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3 years ago

Generate a line up for the 9players on a ball team

Mathematics

1 answer:

Setler79 [48]3 years ago

3 0

Answer:

do a 3 by 3

Step-by-step explanation:

three across and three up

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3.1 4.2 4.3 1.51 5.4 9.2 what is the answer adding it up

olga55 [171]

27.71 is the sum

pls mark me the brainiest

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6 0

3 years ago

Read 2 more answers

What is the distance between the two points? (-18, -6) & (-18,-1)

Hitman42 [59]

Answer:

Step-by-step explanation:

D² = ( x2 - x1 )² + ( y2 - y1 )²

= [ (-18) - (-18) ]² + [ (-1) - (-6) ]²

= ( -1 + 6 )²

D² = ( 5 )²

hence, D = 5

5 0

3 years ago

Read 2 more answers

How do i solve this.

jasenka [17]

Answer:

here is the answer to your question

5 0

2 years ago

Please read and answer the problem and show your work

PilotLPTM [1.2K]

Answer:

x > -4.

Step-by-step explanation:

Solving for x by dividing -3 to both side leaving x by itself.

When dividing or multiplying a negative value that has a variable the inequality switches sides. Instead of x < -4 it is x > -4. For more information or to understand inequality search for inequality video online.

7 0

2 years ago

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

7 0

3 years ago