Question

PLEASE HELP WITH THIS ONE QUESTION

Answer 1

$Hello$ $There!$

$2x^4+16x=0$

$Factor:$ $2x^4+16: 2x(x+2)(x^2-2x+4)$

$2x(x+2)(x^2-2x+4)=0$

You got to used the Zero Factor Principle:

$x=0$  $or$ $x+2=0$ $or$ $x^2-2x+4=0$

$Solve: x+2=0:x=-2$

$Solve: x^2-2x+4=0: x=1+\sqrt{3}i,x=1-\sqrt{3} i$

ANSWER:

$x=0,x=-2,x=1+\sqrt{3} i,x=1-\sqrt{3} i$

Hopefully, this helps you!!

$AnimeVines$