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Svetradugi [14.3K]
2 years ago
7

PLEASE HELP WITH THIS ONE QUESTION

Mathematics
1 answer:
Genrish500 [490]2 years ago
7 0

Hello There!

2x^4+16x=0

Factor: 2x^4+16: 2x(x+2)(x^2-2x+4)

2x(x+2)(x^2-2x+4)=0

You got to used the <u>Zero Factor Principle:</u>

<u></u>

<u></u>x=0  or x+2=0 or x^2-2x+4=0

Solve: x+2=0:x=-2

Solve: x^2-2x+4=0: x=1+\sqrt{3}i,x=1-\sqrt{3} i

<u>ANSWER:</u>

<u></u>

<u></u>x=0,x=-2,x=1+\sqrt{3} i,x=1-\sqrt{3} i<u></u>

<u></u>

Hopefully, this helps you!!

AnimeVines

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Step-by-step explanation:

Given:

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x-3=0\\\Rightarrow x=3

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Horizontal Asymptote is the value of f(x) , where value of x \rightarrow \infty.

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