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Nezavi [6.7K]
3 years ago
12

How do you answer this or what is the answer? Plz and thank you

Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

Step-by-step explanation: pick A, B, AND E. YOU CANT HAVE ANY X VALUES REPEAT.

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PLS HELP GIVING BRAINLESS TO CORRECT PERSON PLS HELP ASAP
irina [24]

Answer:

Correct Answer - It shows the unit rate of the graph in miles per hour.

Step-by-step explanation:

hope this helps

8 0
3 years ago
4 Stretch Your Thinking: Brian has some boxes of paper clips. Some boxes hold 10 clips and some boxes hold 100. He has some pape
rjkz [21]

Answer:02929

Step-by-step explanation:

Oofy

5 0
2 years ago
The length of a parking Lot is 5 yards more than the width. If the area of the parking lot is 66 square yards, find the dimensio
Brums [2.3K]

Answer:

  6 yards by 11 yards

Step-by-step explanation:

Factors of 66 are ...

  66 = 1·66 = 2·33 = 3·22 = 6·11

The last pair of factors differ by 5, so represent the solution to the problem.

The width of the parking lot is 6 yards; the length is 11 yards.

7 0
3 years ago
2. What is the external probability of rolling a 4
Nataly_w [17]

Answer:

2. 1- Experimental probability of rolling a 4 = 40%

3. 2- Theoretical probability is 3%  greater than experimental probability.

Step-by-step explanation:

Experimental probability of rolling a 4 = 100 × \frac{8}{20}

                                                                  = 100 × 0.4

                                                                  = 40%

Experimental probability of getting at least one tail  = \frac{72}{100}

                                                                                    = 0.72

Theoretical probability of getting at least one tail  = \frac{3}{4}

                                                                                  = 0.75

Theoretical probability is 3%  greater than experimental probability.

6 0
3 years ago
Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.
avanturin [10]
In spherical coordinates, we have

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}

which gives volume element

\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

and so the triple integral is given by

\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta
=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi
=\dfrac{592\pi}{15}
4 0
3 years ago
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