Pretty good so far its hard also.
The three points are on the same line, so the slopes formed by any of the two points stay the same
[-7-(-5)]/(-1-0)=[n-(-5)/(1-0)
(n+5)=2
n=-3
(2x-6) + 4(x-3) {distribute 4 out and expand problem}
2x+6+4x-12 {combine like terms}
6x-6 {your answer}
Domain is ur x values
y = 2x...when x = -1
y = 2(-1)
y = -2.....(-1,2) satisfies this equation
y = 2x....when x = 0
y = 2(0)
y = 0....(0,0) satisfies it
y = 2x....when x = 1
y = 2(1)
y = 2....so (1,2) satisfies it
y = 2x....when x = 2
y = 2(2)
y = 4....(2,4) satisfies it
y = 2x...when x = 3
y = 2(3)
y = 6.....(3,6) satisfies it
y = 2x...when x = 4
y = 2(4)
y = 8.....(4,8) satisfies it
Answer:
x + (4/ x-2) + (2/ x-1)
Step-by-step explanation:
x + (6x/ x^2 + 2x - x -2)
x + (6x/ (x + 2) X (x - 1))
(6x/ (x + 2) X (x - 1))
(A/ x+2) + (B/ x-1)
(6x/ (x + 2) X (x - 1)) = (A/ x+2) + (B/ x-1)
6x = Ax + Bx - A + 2B
6x = (A+B)x + (-A+2b)
{0 = -A+2B
{6 = A+B
(A,B) = (4, 2)
(4/ x+2) + (2/ x-1)
x + (4/ x-2) + (2/ x-1)
