Answer:
The scale factor is equal to 1/2
The dimensions of each channel when splits the screen is 46 in x 38 in
Step-by-step explanation:
we know that
The dimensions of the new television is 92 in x 76 in
Remember that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
A1 -----> the area of the new television
A2 ----> the area of each channel when splits the screen
z-----> the scale factor
we have that
The area of the new television is 4 times the area of each channel
-----> the scale factor
so
When splits the screen, the dimension of each channel is equal to
92/2 in x 76/2 in
so
46 in x 38 in
Remember, if two figures are similar then the scale factor is equal to the ratio of their corresponding sides
<em>Verify the value of the scale factor</em>
92/46=1/2
or
76/38=1/2
Complete Question
The complete question is shown on the first uploaded image
Answer:
The calcium level that is the borderline between low calcium levels and those not considered low is 
Step-by-step explanation:
From the question we are told that
The mean is 
The standard deviation 
The proportion of the population with low calcium level is 
5% = 0.05
Let X be a X random calcium level
Now the P(X < c) = 0.05
Here P denotes probability
c is population with calcium level at the borderline
Since the calcium level is normally distributed the z-value is evaluated as
The critical value for 0.05 from the standard normal distribution table is
=> 
substituting values
=> 
=>
Because 1 meter is 1000 millimeters.
32 meters would be 32,000
But there is a decimal point in 3.2, so you would erase one 0.
So 3.2 meters=3,200 millimeters
Y< X^-X-6
1. Solve the x first by factor.
2. X equals to (x-3)(x+2). X=3 or -2.
3. Looking at the problem, we see two similar answers with 3 and -2.
4. The correct answer is D, y=0. Because 0 is less than 3, choice A fails because y is greater than x.
Answer:
Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.
This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.
Take for instance the third question:
This stands true with all three questions.
HOWEVER
I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple. Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.
It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.
If that's case, we can solve it the same way we solved question 20. If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:
Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent. If it is instead a coefficient though, then this would be the answer to it.
